classSolution:defremoveNthFromEnd(self,head,n):# 初始化一个哑节点,它的下一个节点指向链表头节点# 这样做是为了方便处理边界情况,比如删除的是头节点dummy=ListNode(0)dummy.next=head# 初始化快慢指针,初始时都指向哑节点slow=dummyfast=dummy# 快指针先前进n+1步,走到第n+1个节点# 这里加1是为了让快慢...
需要注意一些特殊情况,比如待删除的是第一个元素时,需要返回head.next; Python代码如下: # Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def removeNthFromEnd(self, head, n): """ :type...
Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given n will always be valid. Try to d...
等tmp1访问结束的时候,tmp2刚好访问到倒数第n个节点。 代码(python): View Code
https://leetcode.com/problems/remove-nth-node-from-end-of-list/description/""" # Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = Noneclass Solution(object): def removeNthFromEnd(self, head, n): ...
After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Givennwill always be valid. Try to do this in one pass. 代码:oj在线测试通过 Runtime: 188 ms 1#Definition for singly-linked list.2#class ListNode:3#def __init__(self, x):4#self.val = x5...
Given the head of a linked list, remove the nth node from the end of the list and return its head. The idea is to first find the lengh of the listnode, then count and find the n th node that we want…
first_node=head while flag<len_head-n: first_node=first_node.next flag+=1 #移除节点 first_node.next=first_node.next.next #返回结果 return head 结果: Runtime: 40 ms, faster than 99.22% of Python3 online submissions for Remove Nth Node From End of List....
19. Remove Nth Node From End of List Given a linked list, remove then-th node from the end of list and return its head. Example: Given linked list:1->2->3->4->5,and n=2.After removing the second node from the end,the linked list becomes1->2->3->5. ...
Remove all elements from a linked list of integers that have valueval. 42430 Remove Nth Node From End of List 加一个虚假头结点dummy,并使用双指针p1和p2。p1先向前移动n个节点(从dummy节点开始移动,所以移动了n其实是移动到了前一位),然后p1和p2同时移动... ...