class Solution: # 定义一个方法,用于移除单向链表中的倒数第n个节点 def removeNthFromEnd(self, head, n): # 定义一个递归函数,用于实际执行移除操作 def remove(head): # 如果当前节点为空,则返回0和空节点。这表示已经到达链表末尾。 if not head: return 0, head # 递归调用remove函数处理当前节点的下...
等tmp1访问结束的时候,tmp2刚好访问到倒数第n个节点。 代码(python): View Code
19. Remove Nth Node From End of ListMediumGiven a linked list, remove the n-th node from the end of list and return its head.Example:Given linked list: 1->2->3->4->5, and n = 2.After removing the second node from the end, the linked list becomes 1->2->3->5.Note:Given n...
}// 删除第n个节点// ListNode nthNode = p1.next;p1.next = p1.next.next;// nthNode.next = null;returndummy.next; } }// Runtime: 6 ms// Your runtime beats 100.00 % of java submissions. Python 实现 # Definition for singly-linked list.# class ListNode:# def __init__(self, x...
Leetcode: Remove Nth Node From End of List 题目: Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->...
在Python中,有什么高效的方法可以删除链表的倒数第N个节点? LinkedList的removeNthFromEnd方法的时间复杂度是多少? 19. Remove Nth Node From End of List Given a linked list, remove the n-th node from the end of list and return its head.
After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given n will always be valid. Try to do this in one pass. 题意很简单,就是删除倒数的第n个元素,不过题目要求一次遍历实现。 这个问题的最直接的想法就是两次遍历,首先先遍历一次得到len,然后从正面遍历到...
Runtime: 56 ms, faster than 100.00% of JavaScript online submissions for Remove Nth Node From End of List. 我的第一个运行速度超过所有提交者的解答,^_^ 完整代码 https://github.com/zhoutk/leetcode/blob/master/javascript/qs019_removeNthFromEnd_1.js ...
Write a Python program to remove the nthindex character from a nonempty string. Sample Solution: Python Code: # Define a function named remove_char that takes two arguments, 'str' and 'n'.defremove_char(str,n):# Create a new string 'first_part' that includes all characters from the beg...
19. Remove Nth Node From End of List Given a linked list, remove then-th node from the end of list and return its head. Example: Given linked list:1->2->3->4->5,and n=2.After removing the second node from the end,the linked list becomes1->2->3->5. ...