solution=Solution2() print(solution.removeElements(nums1,2)) print(solution.removeElements(nums2,2)) print(solution.removeElements(nums3,2)) print(nums3) # 暴力法 class Solution: def removeElement1(self, nums: [int], val:int)->int: lens=len(nums) i=lens # 总共需要循环i次,即列表长度...
1publicclassSolution {2publicintremoveElement(int[] A,intelem) {3//Start typing your Java solution below4//DO NOT write main() function5inti=0, j=A.length-1;67while(i<=j){8if(A[i]==elem)9swap(A,i,j--);10else11i++;12}13returnj+1;14}1516publicvoidswap(int[] A,inti,intj...
【LeetCode】27 - Remove Element Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. Solution 1: intremoveElement(vector<int>& nums,intval) { /...
The order of elements can be changed. It doesn't matter what you leave beyond the new length. 示例1: 代码语言:txt AI代码解释 给定nums = [3,2,2,3], val = 3, 函数应该返回新的长度 2, 并且 nums 中的前两个元素均为 2。 你不需要考虑数组中超出新长度后面的元素。
The order of elements can be changed. It doesn't matter what you leave beyond the new length. 要注意的是“It doesn't matter what you leave beyond the new length.” 思路分析:思路很简单,直接上代码。 Solution 1:暴力移动 1classSolution {2public:3intremoveElement(vector<int>& nums,intval){...
The order of elements can be changed. It doesn't matter what you leave beyond the new length. ps:这个题目同样是一个双指针的问题,比较简单,代码如下所示 1classSolution {2public:3intremoveElement(vector<int>& nums,intval) {4intpos =0;5intsz =nums.size();6for(inti =0; i < sz; ++i...
https://discuss.leetcode.com/topic/20654/a-simple-c-solution classSolution{public:intremoveElement(vector<int>& nums,intval){intindex =0;for(inti =0; i != nums.size(); ++i){if(nums[i] != val){ nums[index] = nums[i];
【leetcode】Remove Element Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 题解:用一个len变量记录当前数组的长度。每次遇到元素elem,就把len-1...
https://leetcode.com/problems/remove-element/ Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. ...
[LeetCode]13. Remove Element移除元素 Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length.