1 首先要看你的List是怎么生成的，比如：List<String> strList = Arrays.asList("a", "b", "aa", "ab", "ba");这种方式生成的List是不能改变的（fixed size），具体可以参见源码。2 比如下面这种方式生成的List是可以改变的：List<String> strList2 = new ArrayList<>();strList2.add("a");strLi...
The following Java program usesList.removeIf()to remove multiple elements from the arraylistin java by element value. ArrayList<String>namesList=newArrayList<String>(Arrays.asList("alex","brian","charles","alex"));System.out.println(namesList);namesList.removeIf(name->name.equals("alex"));Syst...
Java: 代码语言:txt AI代码解释 class Solution { public int removeElement(int[] nums, int val) { int i=0,j=nums.length-1;//i-左指针;j-右指针 while (i<=j){ if(nums[i]==val){ nums[i]=nums[j];//得到索引j的值,无需把索引j的值改为索引i的值 j--; }else i++; } return j...
} }returnlist.size() ; //返回数组length } 方法二:采用两个指针,不需要额外空间,数组原地做修改 publicintremoveElement(int[] nums,intval) {//原地修改,不需要额外的空间intnewindex = 0;for(inti = 0; i < nums.length; i++) {if(nums[i] !=val) nums[newindex++] =nums[i]; }returnnewinde...
因此新的方法更适合容易出现异常条件的情况。 peek,element区别: element() 和 peek() 用于在队列的头部查询元素。与 remove() 方法类似,在队列为空时, element() 抛出一个异常,而 peek() 返回 null。
checkElementIndex(index); return node(index).item; } Node node(int index) { if (index < (size >> 1)) { Node x = first; for (int i = 0; i < index; i++) x = x.next; return x; } else { Node x = last; for (int i = size - 1; i > index; i--) ...
1. UsingCollection.removeIf()to Remove Duplicates from OriginalList TheremoveIf()method removes all of the elements of this collection that satisfy a specifiedPredicate. Each matching element is removed usingIterator.remove(). If the collection’s iterator does not support removal, then anUnsupportedOp...
* Removes the element at the specified position in this list. * Shifts any subsequent elements to the left (subtracts one from their * indices). * * @param index the index of the element to be removed * @return the element that was removed from the list ...
if ( s.equals(in) ) { list.remove(s); } } } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 看上去我们的代码很完美,在理论上肯定会达到预期的结果,但是当遍历删除后的array,会发现,打印结果为2,2,1,3,3。怎么还有一个1没删除呢,现在我们来看在这段代码中用到的remove方法 ...
Java迭代器Iterator的remove()方法 遍历Java集合(Arraylist,HashSet...)的元素时,可以采用Iterator迭代器来操作 Iterator接口有三个函数,分别是hasNext(),next(),remove()。 今天浅谈remove函数的作用 官方解释为: Removesfromthe underlying collection the last element returned bythisiterator (optional operation)....