LeetCode#1047-Remove All Adjacent Duplicates In String-删除字符串中的所有相邻重复项 一、题目 给出由小写字母组成的字符串 S,重复项删除操作会选择两个相邻且相同的字母,并删除它们。 在S 上反复执行重复项删除操作,直到无法继续删除。 在完成所有重复项删除操作后返回最终的字符串。答案保证唯一。 示例: 输入...
LeetCode 1047. Remove All Adjacent Duplicates In String (删除字符串中的所有相邻重复项) 题目标签:Stack 利用stack, 把每一个 char 存入 stack 的时候,如果和stack 里的 char 一样,把stack 里的 char 去除。 具体看code。 Java Solution: Runtime: 14 ms, faster than 73.38% Memory Usage: 41.9 MB, ...
LeetCode 1047. Remove All Adjacent Duplicates In String 原题链接在这里:https://leetcode.com/problems/remove-all-adjacent-duplicates-in-string/ 题目: Given a stringSof lowercase letters, aduplicate removalconsists of choosing two adjacent and equal letters, and removing them. We repeatedly make dup...
Can you solve this real interview question? Remove All Adjacent Duplicates in String II - You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them, causing the left and th
1047.Remove All Adjacent Duplicates In String Given a stringSof lowercase letters, aduplicate removalconsists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can.
【Leetcode_easy】1047. Remove All Adjacent Duplicates In String,problem1047.RemoveAllAdjacentDuplicatesInString参考1.Leetcode_easy_1047.RemoveAllAdjacentDuplicatesInString;完
Can you solve this real interview question? Remove Duplicates from Sorted List II - Given the head of a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. Return the linked list sorted
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this by modifyi…
Type:mediun Given a sorted arraynums, remove the duplicatesin-placesuch that duplicates appeared at mosttwiceand return the new length. Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. ...
Do not allocate extra space for another array, you must do this bymodifying the input arrayin-placewith O(1) extra memory. 增加一个count来计数,从左至右遍历,遇到相同的直接del,否则count += 1 classSolution:defremoveDuplicates(self,nums):""" ...