代码(Python3) class Solution: def removeDuplicateLetters(self, s: str) -> str: # last_index[ch] 表示 ch 在 s 中的最后一个出现的位置 last_index: Dict[str, int] = { # 带下标遍历 s 中的字符,更新每个字符最后一次出现的位置 ch: i for i, ch in enumerate(s) } # is_in_stack[ch]...
https://oj.leetcode.com/problems/remove-duplicates-from-sorted-list-ii/ 题目内容: Given a sorted linked list, delete all nodes that have duplicate numbers, leaving onlydistinctnumbers from the original list. For example, Given1->2->3->3->4->4->5, return1->2->5. Given1->1->1->2...
我们一位一位处理字符串,假设处理到了第i位,并且已经得到当前最优的字符串s,如果第i位已经出现在s中,那么就没必要保留这一位了。 如果没有,考虑s的最后一个字母,如果它比最后第i位小,并且在第i位之后还出现了,那么就删掉,直到s为空或者s的最后一个字母不满足条件,把第i位放到最后。 举样例跑一遍: cbacd...
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving onlydistinctnumbers from the original list. For example, Given1->2->3->3->4->4->5, return1->2->5. Given1->1->1->2->3, return2->3. 相对于Remove Duplicates from Sorted List这个问题,这个问题是要把...
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[leetcode]Remove Duplicates from Sorted List II 新博文地址:[leetcode]Remove Duplicates from Sorted List II http://oj.leetcode.com/problems/remove-duplicates-from-sorted-list-ii/ Given a sorted linked list, delete all nodes that have duplicate num......
LeetCode: 82. Remove Duplicates from Sorted List II 题目描述 Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5...
LeetCode 82. Remove Duplicates from Sorted List II 简介:给定已排序的链接列表,删除所有具有重复数字的节点,只留下原始列表中的不同数字。 Description Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list....
* https://discuss.leetcode.com/topic/31404/a-short-o-n-recursive-greedy-solution * 贪心算法 * */ public class Solution { public String removeDuplicateLetters(String s) { if(s==null || s.length()<=0) return ""; else { int[] count=new int[26]; ...
3.代码示例 1classSolution 2{ 3public: 4stringremoveDuplicateLetters(strings) 5{ 6intn=s.size(); 7vector<int>c(26,0),in(26,0); 8for(inti=0;i<n;i++) ++c[s[i]-'a']; 9stringans; 10for(inti=0;i<n;i++) 11{ 12--c[s[i...