算法提高 Quadratic Equation 时间限制:1.0s 内存限制:512.0MB 时间限制:1.0s 内存限制:512.0MB 问题描述 求解方程ax2+bx+c=0的根。要求a, b, c由用户输入,并且可以为任意实数。 输入格式:输入只有一行,包括三个系数,之间用空格格开。 输出格式
蓝桥杯算法提高VIP-Quadratic Equation (C语言代码)水。。 解题思路:无 注意事项:1,scanf()输入double 用%lf printf()输出double 用%f; 2,注意计算的运算顺序; 参考代码: #include<stdio.h> #include<math.h> int main() { double a,b,c; double h; double x1,x2; scanf("%lf%lf%lf",&a,&b,&...
Breadcrumbs noi.openjudge.cn /src /1 /4 / quadratic_equation.cppTop File metadata and controls Code Blame 78 lines (61 loc) · 1.54 KB Raw #include <iostream> #include <iomanip> #include <cmath> #define ERRORS 0.00001 /* quadratic equation */ /* ax^2 + bx + c = 0 */ double ...
Let p = 1000000007. Given two integers b and c, please find two integers x and y(0≤x≤y<p)(0 \leq x \leq y < p)(0≤x≤y<p), such that (x+y) mod p=b(x + y) \bmod p = b(x+y)modp=b (x×y) mod p=c(x \times y) \bmod p = c(x×y)modp=c ...
Program to Find Roots of a Quadratic Equation #include <math.h> #include <stdio.h> int main() { double a, b, c, discriminant, root1, root2, realPart, imagPart; printf("Enter coefficients a, b and c: "); scanf("%lf %lf %lf", &a, &b, &c); discriminant = b * b - 4 ...
问题1484: [蓝桥杯][算法提高VIP]Quadratic Equation 题目描述 求解方程ax2+bx+c=0的根。要求a, b, c由用户输入,并且可以为任意实数。 输入 输入只有一行,包括三个系数,之间用空格格开。 输出 输出只有一行,包括两个根,大根在前,小根在后,保留小数点后两位。 样例输入 2.5 7.5 1.0 样例输出 -0.14 -2.86...
hdu 2394 Johnny and the Quadratic Equation http://acm.hdu.edu.cn/showproblem.php?pid=2394 题目的大概意思就是,判断关于x的二次同余方程 a x^2 + b x + c = 0 ( mod 2 ^32 ) 是否有解 看到这道题目的时候刚好看了一些二次互反律之类的知识,思维被定向到了那边,又在网上找了一些资料,但是都...
to solve quadratic equation ok 31st May 2018, 6:41 PM Moha Äwèl 1 AnswerAnswer + 1 just use the quadratic formula 31st May 2018, 7:08 PM MaxAnswer Often have questions like this? Learn more efficiently, for free: Introduction to Python 7.1M learners Introduction to Java 4.7M learners...
code to solve quadratic equation in python pythonloops 6th Jul 2016, 10:54 AM rishu 3 Respostas Responder + 4 from math import sqrt a,b,c=input(),input(),input() d=b*b-4*a*c print("roots are",(-b+sqrt(d))/(2*a),(-b-sqrt(d))/(2*a) 6th Jul 2016, 5:47 PM Vansh...
I'm trying to code a program in C++ to: ask for 3 integers, display them, and depending on the numbers, use the if code to output results. if the equation is quadratic (a is nonzero) and the roots are real (b2-4ac>=0), compute the root(s) and display them with 3 digits to...