Program to Find Roots of a Quadratic Equation #include <math.h> #include <stdio.h> int main() { double a, b, c, discriminant, root1, root2, realPart, imagPart; printf("Enter coefficients a, b and c: "); scanf("%lf %lf %lf", &a, &b, &c); discriminant = b * b - 4 ...
源代码:/* Program to find roots of a quadratic equation when coefficients are entered by user. */ /* Library function sqrt() computes the square root. */ #include <stdio.h> #include <math.h> /* This is needed to use sqrt() function.*/ int main() { float a, b, c, determinant...
算法提高 Quadratic Equation 时间限制:1.0s 内存限制:512.0MB 时间限制:1.0s 内存限制:512.0MB 问题描述 求解方程ax2+bx+c=0的根。要求a, b, c由用户输入,并且可以为任意实数。 输入格式:输入只有一行,包括三个系数,之间用空格格开。 输出格式
对于二次方程x2 – 4.0000000 x + 3.9999999 = 0,精确到10个有效数字的根是r1 = 2.000316228和r2 = 1.999683772 // C program to demonstrate // double and float precision values #include <stdio.h> #include <math.h> // utility function which calculate roots of // quadratic equation using double...
differential equations C. integral equations D. logarithmic E. quations 相关知识点: 试题来源: 解析 A。“Quadratic equation”(二次方程)属于代数方程(algebraic equations)。微分方程(differential equations)涉及导数;积分方程(integral equations)涉及积分;对数方程(logarithmic equations)涉及对数运算。反馈 收藏 ...
蓝桥杯算法提高VIP-Quadratic Equation (C语言代码)水。。 解题思路:无 注意事项:1,scanf()输入double 用%lf printf()输出double 用%f; 2,注意计算的运算顺序; 参考代码: #include<stdio.h> #include<math.h> int main() { double a,b,c; double h;...
The formula for the quadratic equation is ax²+bx + c = 0, and its solution formula is x = [-b±√(b² - 4ac)]/2a. If a = 1, b = 3, c = 2, how to write this solution formula in English? A. x equals minus b plus or minus the square root of (b squared minus ...
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