>> b = [2; 2; 3];>> lb = [0; 0];>> [x,fval,exitflag,output,lambda] = quadprog(H,f,A,b,[],[],lb)输出以下结果：Warning: Large-scale algorithm does not currently solve this problem formulation,using medium-scale algorithm instead.> In quadprog at 291 Optimization terminated.x =...
exitflag = 1 output = iterations: 2 constrviolation: 0 algorithm: 'medium-scale: active-set' firstorderopt: [] cgiterations: [] message: 'Optimization terminated.' lambda = lower: [2x1 double] upper: [2x1 double] eqlin: [0x1 double] ineqlin: [2x1 double] 输出中的warning说明 quadpr...
exitflag = 1 例2:求解:二次规划问题 min +x12+2x22-2x1x2-4x1-12x2 s.t x1+x2≤2 -x1+2x2≤2 2x1+x2≤3 0≤x1, 0≤x2 程序: H=[2 -2;-2 4]; f=[-4;-12]; A=[1 1;-1 2;2 1]; b=[2;2;3]; lb=zeros(2,1); [x,fval,exitflag]=quadprog(H,f,A,b,[],[],...
fval,exitflag,output,lambda]=quadprog(H,f);%求取最小值时x值% x:满足最小取值的x的值% fval: 1/2*x'*H*x + f'*x在x处最小值解% exitflag:运算停止的原因,1:找到了结果;0:超出范围;还有其他值value=0.5*x(1)^2+x(2)^2-x(1)*x(2)-2*x(1)-6*x(2);%求f(x)最小值...
0?>= x1，0?>= x2 n解：把⼆次规划问题写成标准形式：(1/2)XTHX+fTX 这⾥：H= 1 -1 f= -2 X= x1 -1 2 -6 x2 nH=[1 -1;-1 2];f=[-2;-6];A=[1 1;-1 2;2 1];b=[2;2;3];lb=zeros(2,1);[x,fval,exitflag,output,lambda]=quadprog(H,f,A,b...