list1 = [1,2,3] list2 = [4,5,6] concatenated_list = list1 + list2print(concatenated_list) 使用extend()方法: list1 = [1,2,3] list2 = [4,5,6] list1.extend(list2)print(list1) 使用列表解析: list1 = [1,2,3] list2 = [4,5,6] concatenated_list = [itemforsublistin[lis...
1] # Check for Sublist in List # Using loop + list slicing res = False for idx in range...
示例代码: nested_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] for sublist in nested_list: for item in sublist: print(item, end=' ') print() 复制代码 使用列表推导式: 使用嵌套的列表推导式将嵌套列表展开,并用print语句输出。 示例代码: nested_list = [[1, 2, 3], [4, 5, ...
我已经尝试过这些功能,但不起作用: list_flat = [item for sublist in list for item in sublist] and flat_list = [] for sublist in t: for item in sublist: flat_list.append(item) >>> l1 = [ ... ({'item1', 'item2'}, 'item_a'), ... ({'item1', 'item2'}, 'item_b'),...
result = [item for sublist in [list1, list2, list3] for item in sublist] print(result) # 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9] 1. 2. 3. 4. 5. 6. 7. 使用itertools.chain() itertools.chain()函数可以将多个可迭代对象连接成一个迭代器。
方法4: 使用列表推导式 list_of_lists = [[1, 2, 3], [4, 5, 6]] merged_list = [item for sublist in list_of_lists for item in sublist] print(merged_list) # 输出: [1, 2, 3, 4, 5, 6] 你可以根据自己的需求选择合适的方法。
list1 = [1, 2, 3]list2 = [4, 5, 6]merged_list = [item for sublist in [list1, list2] for item in sublist]print(merged_list) # 输出: [1, 2, 3, 4, 5, 6]方法四：使用itertools.chain()itertools.chain()函数是Python标准库中itertools模块提供的一个函数，它可以将多个迭代器链接...
list_of_lists=[[1,2,3],[4,5,6],[7,8,9]]merged_list=[]forsublistinlist_of_lists:merged_list.extend(sublist)print(merged_list) 1. 2. 3. 4. 5. 6. 7. 上述代码首先定义了一个包含多个子列表的列表list_of_lists。然后,我们创建了一个空列表merged_list,用于存储合并后的结果。
# 创建一个嵌套列表nested_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]# 使用列表推导式展平嵌套列表flattened_list = [item for sublist in nested_list for item in sublist]print(flattened_list) # 输出: [1, 2, 3, 4, 5, 6, 7, 8, 9] ...
print(flattened_list) # 输出: [1, 2, 3, 4, 5, 6] 2. 列表推导 def flatten_list(lst): return [item for sublist in lst for item in sublist] # 示例 nested_list = [1, [2, 3], [4, [5, 6]]] flattened_list = flatten_list(nested_list) print(flattened_list) # 输出: [1, ...