我们可以定义一个测试函数来验证 rotate_matrix 的正确性。 python def test_rotate_matrix(): matrix = [ [1, 2, 3], [4, 5, 6], [7, 8, 9] ] rotated_matrix = rotate_matrix(matrix) # Expected result after rotating 90 degrees clockwise expected_result = [ [7, 4, 1], [8, 5, 2...
关键词: 1、matrix: 矩阵 2、2D matrix: 二维矩阵 3、rotate: 旋转 4、clockwise: 顺时针 5、90 degrees: 90度 即:我们需要将一个二维矩阵顺时针旋转90度。 理解题意之后,我们还需要关注下题目中额外的要求,即 note 部分,关键词: 1、in-place: 原地修改 2、do not allocate another 2D matrix: 不能新...
matrix[i].reverse()#然后将矩阵的每一行翻转returnmatrix 解题思路2:首先沿着副对角线翻转一次,然后沿着水平中线翻转一次,就可以得到所要求的矩阵了。时间复杂度O(n^2),空间复杂度O(1) classSolution:#@param matrix, a list of lists of integers#@return a list of lists of integersdefrotate(self, matrix...
Matrix(arr): for i in range(R): for j in range(C): print(str(arr[i][j]), end =" ") print() def rotate90(arr): transpose(arr) reverseColumns(arr) arr = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16] ]; rotate90(arr) printMatrix(arr...
leetcode 【 Rotate Image 】python 实现 题目: You are given annxn2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? 代码:oj测试通过 Runtime: 53 ms 1classSolution:2#@param matrix, a list of lists of integers3#@return a...
def rotate_bound(image, angle): # grab the dimensions of the image and then determine the # center (h, w) = image.shape[:2] (cX, cY) = (w / 2, h / 2) # grab the rotation matrix (applying the negative of the # angle to rotate clockwise), then grab the sine and cosine ...
定义旋转角度theta=np.pi/2# 90 degrees in radians# 定义旋转矩阵R=np.array([[np.cos(theta),-np.sin(theta)],[np.sin(theta),np.cos(theta)]])# 定义原始点point=np.array([1,0])# 计算旋转后的点rotated_point=np.dot(R,point)print("原始点:",point)print("旋转后的点:",rotated_point...
Rotate an array by 90 degrees in the plane specified by axes. Rotation direction is from the first towards the second axis. k: Number of times the array is rotated by 90 degrees. 关键参数k表示旋转90度的倍数,k的取值一般为1、2、3,分别表示旋转90度、180度、270度;k也可以取负数,-1、-2...
类似地,numpy.degrees()可以将弧度数组转换为角度: import numpy as np 创建一个弧度数组 angles_radians = np.array([0, np.pi/6, np.pi/4, np.pi/3, np.pi/2, np.pi, 2*np.pi]) angles_degrees = np.degrees(angles_radians) print("Angles in radians:", angles_radians) ...
Output:a matrix Conditions:rotate 90 degrees clockwise 题目思路 注意到是将原来的矩阵顺时针旋转90度,本来直接转换比较费劲,网上大神说先转置然后每一行reverse即得所求,仔细观察矩阵的构造,的确如此,代码就几行……注意观察,不一定要一步得出答案。