# Quick examples of removing substring from stringimportre# Initialize the stringstring="Welcome To SparkByExamples Tutorial"# Example 1: Using replace() method# to remove substring from stringsubstr_to_remove="Tutorial"result=string.replace(substr_to_remove,"")# Example 2: Using string slicing ...
In order to avoid thisTraceback Error, we can use the keywordinto check if a substring is contained in a string. In the case of Loops, it was used for iteration, whereas in this case it’s a conditional that can be eithertrueorfalse.It’ll be true if the substring is part of the ...
a nice string representation of the object. | If the argument is a string, the return value is the same object. | | Method resolution order: | str | basestring | object | | Methods defined here: | | __add__(...) | x.__add__(y) <==> x+y | | __contains__(...) | x...
ValueError: substring not found >>> str.index("n") #同find类似,返回第一次匹配的索引值 4 >>> str.rindex("n") #返回最后一次匹配的索引值 11 >>> str.count('a') #字符串中匹配的次数 0 >>> str.count('n') #同上 2 >>> str.replace('EAR','ear') #匹配替换 'string learn' >...
| Return the number of non-overlapping occurrences of substring sub in | string S[start:end]. Optional arguments start and end are | interpreted as in slice notation. | | encode(...) | S.encode(encoding='utf-8', errors='strict') -> bytes ...
Return a copy of the string with all occurrences of substring old replaced by new. If the optional argument count is given, only the first count occurrences are replaced. >>> b='abc123efe12abcde1212' >>> b.replace('12','AB') 'abcAB3efeABabcdeABAB' >>> b.replace('12','AB',1)...
If tabsize is not given, a tab size of 8 characters is assumed. """ pass def find(self, sub, start=None, end=None): # real signature unknown; restored from __doc__ """ S.find(sub[, start[, end]]) -> int Return the lowest index in S where substring sub is found, ...
S.replace(old, new[, count]) -> string Return a copy of string S with all occurrences of substring old replaced by new. If the optional argument count is given, only the first count occurrences are replaced. """ print s.replace('\t','') ...
string re pos endpos 方法: group() :分组,返回字符串 groups():分组,返回以括号内的内容组成的元祖 start() end() re.search():第一次匹配到的字符,返回match对象 re.findall():匹配到的所有字符,返回一个列表 re.finditer():匹配到的所有字符,返回一个迭代器,内容是math对象 re.split(“m”,str):...
Replace the newline character with an empty string: print(s.replace('\n','')) Copy The output is: Output abcdef Copy The output shows that both newline characters (\n) were removed from the string. Remove a Substring from a String Using thereplace()Method ...