To get a substring from a string in Python, you can use the slicing operator string[start:end:step]. The slice operator returns the part of a string between the "start" and "end" indices. The "step" parameter specifies how many characters to advance after extracting the first character ...
count(sub[, start[, end]]) -> int 32 33 Return the number of non-overlapping occurrences of substring sub in 34 string S[start:end]. Optional arguments start and end are interpreted 35 as in slice notation. 36 """ 37 return 0 38 39 def decode(self, encoding=None, errors=None): ...
a nice string representation of the object. | If the argument is a string, the return value is the same object. | | Method resolution order: | str | basestring | object | | Methods defined here: | | __add__(...) | x.__add__(y) <==> x+y | | __contains__(...) | x...
| S.translate(table [,deletechars]) -> string | '''根据参数table给出的表(翻译表,翻译表是通过maketrans方法转换而来)转换字符串的字符, 要过滤掉的字符放到 del 参数中''' | Return a copy of the string S, where all characters occurring | in the optional argument deletechars are removed, and...
: count(str, beg=0, end=len(string)) : -- 搜索的子字符串 -- 字符串开始搜索的位置。默认第一个字符,第一个字符索引值为0。 -- 字符串中结束搜索的位置。字符第一个字符的索引为 0。默认字符串的最后一个位置。 值: 该方法返回子字符串在字符串中出现的次数。
) S.find(sub [,start [,end]]) -> int Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 on failure. In [102]: s1.find("i") #元素第一次...
S.replace(old, new[, count]) -> string Return a copy of string S with all occurrences of substring old replaced by new. If the optional argument count is given, only the first count occurrences are replaced. """ print s.replace('\t','') ...
delete(1,6) s1.display() print('\n将s2连接到s1的后面') s1.concat(s2) s1.display() print('\n返回s1位置1-5的子串') s3 = s1.subString(1,6) s3.display() print('\n判断s1和s3的大小') print(s1.compareTo(s3)) 输出结果如下 1 2 3 4 5 6 在位置1插入s2 1 1 2 3 4 5 6...
return[False,True][len(strString)>6] importtimeit print(timeit.timeit('isLen1("5fsdfsdfsaf")',setup="from __main__ import isLen1")) print(timeit.timeit('isLen("5fsdfsdfsaf")',setup="from __main__ import isLen")) contextlib ...
# 结果:ValueError: substring not found # rindex(self, sub, start=None, end=None): # 从右往左查询 ###判断是否是字母和数字(isalnum)### 判断字符串中只能包含 字母和数字 # isalnum(self) # 判断是否是字母和数字 aa = "beijing Tami KEJI YouXian GongSi 111" print...