return nth fibonacci number 1. 2. 这个程序可以看出是一个伪代码,定义了函数后,将return翻译一下就是返回第n个斐波那契数列的数值,这也是做程序员必须掌握的吧,首先需要看懂伪码,然后写下自己的伪码,再最后构建真实的代码,这或许比直接写出能运行的代码更加真实,而大部分人却选择了跳过前面两步,最后造成结果就...
# A program to compute the nth Fibonacci number where n is a value input by the user def fibonacci(n): if n <= 0: raise ValueError("n must be positive") elif n < 2: return n fib_n_minus_one = 1 fib_n_minus_two = 0 fib_n = 0 for _ in range(2, n + 1): fib_n =...
print('The #2 Fibonacci number is 1.') continue # Display warning if the user entered a large number: if nth >= 10000: print('WARNING: This will take a while to display on the') print('screen. If you want to quit this program before it is') print('done, press Ctrl-C.') inpu...
''')whileTrue:# Main program loop.whileTrue:# Keep asking until the user enters valid input.print('Enter the Nth Fibonacci number you wish to')print('calculate (such as 5, 50, 1000, 9999), or QUIT to quit:') response =input('> ').upper()ifresponse =='QUIT':print('Thanks for ...
print('0, 1')print()print('The #2 Fibonacci number is 1.')continue# Display warningifthe user entered a large number:ifnth>=10000:print('WARNING: This will take a while to display on the')print('screen. If you want to quit this program before it is')print('done, press Ctrl-C....
num = float(input("请输入一个数字:")) if num > 0: print(f"{num} 是正数") elif num < 0: print(f"{num} 是负数") else: print(f"{num} 是零") 首先,使用input()函数获取用户输入的数字,并将其转换为float类型。然后使用if-elif-else语句进行判断,如果num大于0,则打印“输入的数字为正数”...
0132 🎯 Print the Longest String ★☆☆ Start Challenge 0133 🎯 Remove all Duplicate Words ★☆☆ Start Challenge 0134 🎯 Generating the Nth Fibonacci Number ★☆☆ Start Challenge 0135 🎯 Capitalize Last Letter of Words ★★☆ Start Challenge 0136 🎯 Shifting Letters in Sentences ★★...
Generators, in general, are used to create iterators with a different approach. They employ the use of yield keyword rather than return to return a generator object.Let's try and build a generator for fibonacci numbers -## generate fibonacci numbers upto n def fib(n):...
1#A program to compute the molecular weight of a hydrocarbon2importmath3defmain():4hydrogen_atoms = float(input("Please enter the number of hydrogen atomes:"))5carbon_atoms = float(input("Please enter the number of carbon atomes:"))6oxygen_atoms = float(input("Please enter the number of...
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