return nth fibonacci number 1. 2. 这个程序可以看出是一个伪代码,定义了函数后,将return翻译一下就是返回第n个斐波那契数列的数值,这也是做程序员必须掌握的吧,首先需要看懂伪码,然后写下自己的伪码,再最后构建真实的代码,这或许比直接写出能运行的代码更加真实,而大部分人却选择了跳过前面两步,最后造成结果就...
# A program to compute the nth Fibonacci number where n is a value input by the user def fibonacci(n): if n <= 0: raise ValueError("n must be positive") elif n < 2: return n fib_n_minus_one = 1 fib_n_minus_two = 0 fib_n = 0 for _ in range(2, n + 1): fib_n =...
print('The #2 Fibonacci number is 1.') continue # Display warning if the user entered a large number: if nth >= 10000: print('WARNING: This will take a while to display on the') print('screen. If you want to quit this program before it is') print('done, press Ctrl-C.') inpu...
''')whileTrue:# Main program loop.whileTrue:# Keep asking until the user enters valid input.print('Enter the Nth Fibonacci number you wish to')print('calculate (such as 5, 50, 1000, 9999), or QUIT to quit:') response =input('> ').upper()ifresponse =='QUIT':print('Thanks for ...
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deftest_08_v0(n):# Baseline version (Inefficient way)# (Inefficiently calculates the nth Fibonacci# number using a list)ifn <=1:returnn f_list = [0,1]foriinrange(2, n +1): f_list.append(f_list[i -1] + f_list[i -2])returnf_list[n]deftest_08_v1(n):# Improved version...
Python Program to Print Fibonacci Series until ‘n’ value using recursion 1 2 3 4 5 6 7 8 def fib(digit): if digit <= 1: return (digit) else: return (fib(digit-1) + fib(digit-2)) number_of_digit = 5 for i in range(number_of_digit): print(fib(i)) You’ll also like:...
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print('0, 1')print()print('The #2 Fibonacci number is 1.')continue# Display warningifthe user entered a large number:ifnth>=10000:print('WARNING: This will take a while to display on the')print('screen. If you want to quit this program before it is')print('done, press Ctrl-C....