ref: Get the path of the current file (script) in Python: __file__ To get the directory of the current Python file, you can use the os.path module in combination with the __file__ attribute. Here's how you can do it: import os # Get the directory of the current Python file ...
1. 2. Next, wherever you want to find the source file from you just use abspath(getsourcefile(lambda:0))ref: http://stackoverflow.com/questions/2632199/how-do-i-get-the-path-of-the-current-executed-file-in-python 1.
path1='/dir1/dir2/file.txt'path2='/dir1/dir2/file.txt/'print('__file__ =',__file__)print('path1 =', path1)print('path2 =', path2)#Return the directory name of pathname path.#This is the first element of the pair returned#by passing path to the function split().print('...
FILE_TYPE_PAT: ('.pat', ), FILE_TYPE_MOD: ('.mod', ), FILE_TYPE_LIC: ('.xml', '.dat', '.zip'), FILE_TYPE_FEATURE_PLUGIN : ('.ccx', ), FILE_TYPE_USER: (None, ) } FLASH_HOME_PATH = '{}'.format('/opt/vrpv8/home') # Record the name of the startup information ...
Write a Python program to retrieve the path and name of the file currently being executed.Sample Solution:Python Code:# Import the 'os' module to work with the operating system. import os # Use the 'os.path.realpath(__file__)' to get the full path of the current Python script. # ...
new_path = os.path.join('archive', file_name) shutil.move(file_name, new_path) 而且,由于不同的操作系统使用的分隔符不同,使用字符串拼接路径就容易出现问题。 有了pathlib,使得上述的问题变得更加轻松,pathlib创建的Path对象,可以直接通过正斜杠运算符/连接字符串生成新的对象。
# 导入xlwings模块import xlwings as xw# 打开Excel程序,默认设置:程序可见,只打开不新建工作薄,屏幕更新关闭app=xw.App(visible=True,add_book=False) app.display_alerts=False app.screen_updating=False# 文件位置:filepath,打开test文档,然后保存,关闭,结束程序filepath=r'g:\Python Scripts\test.xlsx' wb=...
"Hellow Video"', default='This is demo example')parser.add_argument( '-s', type=int, help='The font size of video watermark. ' + 'ex. 30', default='30')parser.add_argument( '-n', type=str, help='The new file name.\n' + 'Default value is {current file name}_title.mp4',...
from os.path import join, isfile, isdir def listDirDepthFirst(directory): '''深度优先遍历文件夹''' #遍历文件夹,如果是文件就直接输出 #如果是文件夹,就输出显示,然后递归遍历该文件夹 for subPath in listdir(directory): path = join(directory, subPath) ...
def load_scan(path):slices = [dicom.read_file(path + '/' + s) for s in os.listdir(path)]slices.sort(key = lambda x: float(x.ImagePositionPatient[2]))try:slice_thickness = np.abs(slices[0].ImagePositionPatient[2] - slices[1].ImagePositionPatient[2])except:slice_thickness = np....