def module_path(local_function): ''' returns the module path without the use of __file__. Requires a function defined locally in the module. from http://stackoverflow.com/questions/729583/getting-file-path-of-imported-module''' return os.path.abspath(inspect.getsourcefile(local_function)) ...
file_path = Tools.getPathFromView(view)if(commandandnotsketch_size): self.message_queue.put('not_empty_sketch_{0}', current_time)# current file / viewcurrent_path = Paths.getCurrentFilePath(view)if(notcurrent_path):returnself.is_iot = Tools.isIOTFile(view) current_dir = Paths.getCWD(...
First, you need to import frominspectandos frominspectimportgetsourcefilefromos.pathimportabspath Next, wherever you want to find the source file from you just use abspath(getsourcefile(lambda:0)) ref: http://stackoverflow.com/questions/2632199/how-do-i-get-the-path-of-the-current-executed-fi...
#将文件路径和文件名分割(会将最后一个目录作为文件名而分离)os.path.split(filename) #将文件路径和文件扩展名分割成一个元组os.path.splitext(filename) #返回文件路径的目录部分os.path.dirname(filename) #返回文件路径的文件名部分os.path.basename(filename) #将文件路径和文件名凑成完整文件路径os.path.j...
File"<stdin>", line1,in<module> FileNotFoundError: [WinError2] The system cannot find the file specified:'C:/ThisFolderDoesNotExist' os模块中的os.getcwd()函数是以前获取字符串形式的 CWD 的方法。 绝对路径与相对路径 有两种方法可以指定文件路径: ...
File "<stdin>", line 1, in <module> AttributeError: 'module' object has no attribute 'Path' 原因: sys模块没有Path属性。 解决方案: python对大小写敏感,Path和path代表不同的变量。将Path改为path即可。 >>> sys.path ['', '/usr/lib/python2.6/site-packages'] ...
I am searching for a good way to get relative paths of files and (sub)folders within a specific folder. For my current approach I am using os.walk(). It is working but it does not seem "pythonic" to me: myFolder = "myfolder" fileSet = set() # yes, I need a set...
在下文中一共展示了FileManager.get_current_path方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。 示例1: FileManagerTest ▲点赞 7▼ # 需要导入模块: from FileManager import FileManager [as 别名]# 或者: from ...
path.basename(script_path) # 获取当前脚本所在的文件夹目录 script_directory = os.path.dirname(script_path) # 获取当前的工作路径 search_path = os.getcwd() # 获取目录下包含的文件夹和文件 dir_list=os.listdir(search_path) 3 文件夹判断 # 判断文件是否存在 if os.path.exists(file_path) #判断...
Python语言中当前工作目录(Current Wo,相关:查thon3.7版本)本文主要解释Python语言中的两个基本概念:当前工作目录(CurrentWorkingDirectory,cwd)模块第一搜索路径先说明下,本文是在Ubu