# printing original listprint("The original list : "+ str(test_list)) # using set() + sorted()# removing duplicate sublistres = list(set(tuple(sorted(sub))forsubintest_list)) # print resultprint("The list after duplicate removal :...
The original list : [[1, 0, -1], [-1, 0, 1], [-1, 0, 1], [1, 2, 3], [3, 4, 1]]The list after duplicate removal : [(-1, 0, 1), (1, 3, 4), (1, 2, 3)] 也可以利用 set() + map() + sorted()...
defremove_duplicates(lst): unique_list=[] [unique_list.append(item)foriteminlstifitemnotinunique_list] returnunique_list # 示例 original_list=[1,2,2,3,4,4,5] unique_list=remove_duplicates(original_list) print(unique_list)# 输出: [1, 2, 3, 4, 5] 删除两个列表中重复的元素 在以下...
print ("The original list is : " + str(test_list))# using naive method # to remove duplicated # from list res = []for i in test_list:if i not in res:res.append(i)# printing list after removal print ("The list after removing duplicates : " + str(res))→输出结果：The ...
If you need to de-duplicate while maintaining the order of your items, use dict.fromkeys instead:>>> unique_items = list(dict.fromkeys(original_items)) That will de-duplicate your items while keeping them in the order that each item was first seen....
class Solution: def removeDuplicateLetters(self, s: str) -> str: # last_index[ch] 表示 ch 在 s 中的最后一个出现的位置 last_index: Dict[str, int] = { # 带下标遍历 s 中的字符,更新每个字符最后一次出现的位置 ch: i for i, ch in enumerate(s) } # is_in_stack[ch] 表示 ch 是否...
defremove_duplicates_with_comprehension(lst):seen=set()return[xforxinlstifnot(xinseenorseen.add(x))]# 示例original_list=[1,2,2,3,4,4,5]new_list=remove_duplicates_with_comprehension(original_list)print(f"原始列表:{original_list}")print(f"去重后的列表:{new_list}") ...
print(mylist) Create a dictionary, using the List items as keys. This will automatically remove any duplicates because dictionaries cannot have duplicate keys. Create a Dictionary mylist = ["a","b","a","c","c"] mylist = list(dict.fromkeys(mylist)) ...
# using naive method to remove duplicated from list res = [] for i in test_list: if i not in res: res.append(i) # printing list after removal print ("The list after removing duplicates : " + str(res)) # 输出结果: # 原始列表是:[1, 3, 5, 6, 3, 5, 6, 1] ...
2.使用列表推导式（List comprehension）：def remove_duplicates(arr): return [x for i, x in...