下面是一个示例代码: array=[1,2,3,4,5]last_element=array[len(array)-1]print(last_element) 1. 2. 3. 输出结果为: 5 1. 在这个示例中,数组array包含了5个元素,使用len(array) - 1的索引来获取最后一个元素,并将其赋值给变量last_element。然后通过print函数打印出最后一个元素的值。 2. 使用负...
for item in example_array: print(item) The output returns the value of every element in the array. 2 4 6 8 Using the enumerate function, you simultaneously loop through the elements and their indices: for i, item in enumerate(test_array): print(str(i + 1) + ": " + str(item))...
下面是一个示例代码,演示如何提取数组中符合特定条件的元素: # 创建一个数组array=[1,2,3,4,5]# 提取大于3的元素greater_than_3=[]forelementinarray:ifelement>3:greater_than_3.append(element)print('大于3的元素:',greater_than_3) 1. 2. 3. 4. 5. 6. 7. 8. 9. 运行以上代码,输出结果为:...
remove(1) Traceback (most recent call last): File "", line 1, in <module> ValueError: array.remove(x): x not in list 删除array 所有的 1 from array import array def delete_array_element(): arr = array('i', [1, 2, 1, 4, 1, 11, 1, 2, 1, 2, 0, 1, 2, 1, 4]) wh...
def add_last(self, e): cap = len(self.data) if self.size == cap: self._resize(2 * cap) self.data[self.size] = e self.size += 1 删除一个元素(位置无要求) 代码语言:python 代码运行次数:0 运行 AI代码解释 def remove(self, index): self._check_element_index(index) cap = len(se...
x = [i*j for i in range(100) for j in range(10)] x = [i for i in range(10) if i % 2 ==0] x = [[0 for _ in range(5)] for _ in range(5)] # create 2D array x = {char: sentence.count(char) for char in set(sentence)} ...
1-D Array Indexing Use bracket notation[ ]to get the value at a specific index.Remember that indexing starts at 0. 1importnumpy as np2a=np.arange(12)3a4#start from index 05a[0]6#the last element7a[-1] Output: array([ 0,1,2,3,4,5,6,7,8,9, 10, 11]) ...
1、任何两个大小相等的数组之间的运算,都是element-wise(点对点) arr = np.array([[1., 2., 3.], [4., 5., 6.]]) array([[1., 2., 3.], [4., 5., 6.]]) arr*arr array([[1., 4., 9.], [16., 25., 36.]])
In [1]: vowels = ['a', 'e', 'i', 'o', 'u'] In [2]: vowels Out[2]: ['a', 'e', 'i', 'o', 'u'] 我们可以不添加任何元素来初始化一个列表: In [3]: array_init = [] In [4]: array_init Out[4]: [] 如果要提取列表中的元素,使用索引是一种方法,将索引值写在变量名...
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