y_true, y_pred = np.array(y_true), np.array(y_pred) return np.mean(np.abs((y_true - y_pred) / y_true)) * 100 二、基准模型:Last value 和移动均线方法 在Last Value方法中,我们将简单地将预测设置为最后一个观测值。这意味着我们将当前的复权收盘价设置为前一天的复权收盘价。这是最具成...
ArrayIndex : + get_last_index(arr: List[int]) -> int 在类图中,定义了一个ArrayIndex类,其中包含一个get_last_index()方法用于获取数组中元素的最后一个索引位置。通过类的封装和方法的调用,可以更好地实现对数组索引位置的判断和获取。
The MAX function will find the maximum value from the previous result, that will return as 13 SUMPRODUCT(MAX(ROW($B$5:$B$13)*($E$7=$B$5:$B$13))-4) The SUMPRODUCT function is used to find the row number in the array. As our list starts from the 5th row onwards, 4 has bee...
You can get the last N elements of a list in Python, you can useslicingwith a negative index. For example, you can initialize a list calledmylistwith8integer values, and a variableNwith a value of3and usenegative indexingto slice the list. The expressionmylist[-N:]will return a new ...
The data property “seniorRating“ is already declared as a prop. Use prop default value instead 报错: The data property “seniorRating” is already declared as a prop. Use prop default value instead 原因:在父组件中定义的自定义属性往子组件中传值的时候,子组件中的data中也命名了一个相同的。
When processing data in Python, we often want to maintain a subset of the most recent elements from a collection. Whether it’s a list, NumPy array, or a string, there are various ways to achieve this efficiently. This tutorial will explore different methods to keep the last N items using...
pythonarraylast #Python数组的最后一个元素:一个深入探讨 在数据科学和程序开发中,数组(list)是存储和操作数据的一种基本数据结构。作为Python中最常用的数据类型之一,数组使得我们能够灵活地处理和访问数据。在这篇文章中,我们将讨论如何获取Python数组的最后一个元素,包括相关的代码示例和一些实际应用场景。 ##Python...
1. Problem Descriptions:Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value.If target is not found in the array, return [-1…
array.findLast(function(currentValue, index, arr),thisValue) Parameters function()Required. A function to run for each array element. currentValueRequired. The value of the current element. indexOptional. The index of the current element. ...
const numbers = [1, 3, 5, 7, 9]; const lastValue = numbers.findLast((num) => num % 2 === 0); document.write(lastValue); Output It returns 'undefined' as result because, no element in the array satisfies the function. undefined Print Page Previous Next...