返回True,否则返回False# 检查数字能否被5整除is_divisible_by_5=number%5==0# 如果能够整除,返回True,否则返回False# 输出结果ifis_divisible_by_3andis_divisible_by_5:print(f"{number}可以被3和5同时整除")elifis_divisible_by_3
步骤2:判断是否被3整除 接下来,我们需要判断这个数字是否能被3整除。我们可以使用取余操作符%来实现。 # 判断是否被3整除is_divisible_by_3=num%3==0 1. 2. 步骤3:输出结果 最后,我们根据判断结果输出相应的信息,并计算余数。 # 输出结果ifis_divisible_by_3:print("True")else:print("False")remainder=...
void function fizzbuzz For (i = 1; i <= 100; i++) { set print_number to true; If i is divisible by 3 print "Fizz"; set print_number to false; If i is divisible by 5 print "Buzz"; set print_number to false; If print_number, print i; print a newline; } 请注意大括号...
lst=[]foriinrange(50):ifi%3==0:lst.append(i)print(f"numbers divisible by 3: {lst}") 执行结果是: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 %python divisibility.py numbers divisible by3:[0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48] 其实,如果读者认真阅读range()...
3. and还可以用于多个条件的组合。例如，判断一个数是否为偶数且能被3整除：def is_even_and_divisible_by_3(num):(tab)if num % 2 == 0 and num % 3 == 0:(tab)(tab)return True(tab)else:(tab)(tab)return Falseprint(is_even_and_divisible_by_3(6)) # 输出Trueprint(is_even_and_...
is_divisible(6,3) True 在函数内部,==运算符的结果是一个布尔值,因此我们可以通过直接返回它来更简洁地编写这个函数。 defis_divisible(x, y):returnx % y ==0 布尔函数通常用于条件语句中。 ifis_divisible(6,2):print('divisible') divisible ...
if a % b == 0: return f”{a} is divisible by {b}.” return f”{a} is not divisible by {b}.” print(check_divisible(10, 2)) # 输出结果为10 is divisible by 2. print(check_divisible(10, 3)) # 输出结果为10 is not divisible by 3. ...
3.常用操作运算等 与其他类似,+,-,*,/,% 其中整数除法还是整数。如要结果是小数,必须是点除./ 4.条件控制语句 格式如下: if<条件式子>: 语句一elif<条件式子>: 语句二else: 语句三 实际情况中,可只有if,或if…else… 5.循环体 1)for循环
By "useful" we mean factors # less than MAX_KEY_LENGTH + 1 and not 1\. For example, # getUsefulFactors(144) returns [2, 3, 4, 6, 8, 9, 12, 16]. if num < 2: return [] # Numbers less than 2 have no useful factors. factors = [] # The list of factors found. # When...
How to Check if a Number Is Even or OddIn this section, you’ll see how you can use the modulo operator to determine if a number is even or odd. Using the modulo operator with a modulus of 2, you can check any number to see if it’s evenly divisible by 2. If it is evenly ...