False 4 divisible by 2 or 3? True 4 divisible by 2 or 3, but not both? True n = int(input()) print(n, 'divisible by 2 and 3?', n % 2 == 0 and n % 3 == 0) print(n, 'divisible by 2 or 3?', n % 2 == 0 or n % 3 == 0) print(n, 'divisible by 2 or 3...
(1)能被2和3都能整除 (2)能被2整除但不能被3整除 (3)不能被2整除但是能被3整除 2.用if 整除问题 % 多重if 嵌套 代码: x=eval(input("请随机输入一个数:")) if x%2 ==0: if x%3 ==0: print("Divisible by 2 and 3 .") else: print("Divisible by 2 and not by 3 .") elif x...
print 'The number', i, 'is divisible by 2.' for j in range(20,100): print j if j > 22: break; [输出] $ python example12_break_continue.py The number 0 is divisible by 2. The number 2 is divisible by 2. The number 4 is divisible by 2. The number 6 is divisible by 2. ...
if x%2 == 0: if x%3 == 0: print 'Divisible by 2 and 3' else: print 'Divisible by 2 and not by 3' elif x%3 == 0: print 'Divisible by 3 and not by 2' 上面代码中的elif表示“else if”。在条件语句的测试中使用复合布尔表达式是很方便的,例如: if x < y and x < z: ...
y = x ** 2 + 5 z = (x + y) * (x - y) 1. 2. 3. 4. 5. 6. 7. 你还可以将此应用于有多个条件的if语句: # Not recommended if x > 5 and x % 2 == 0: print('x is larger than 5 and divisible by 2!') 1.
y = x**2 + 5 z = (x+y) * (x-y) # Not Recommended y = x ** 2 + 5 z = (x + y) * (x - y) 你还可以将此应用于有多个条件的if语句: # Not recommended if x > 5 and x % 2 == 0: print('x is larger than 5 and divisible by 2!') ...
Let's use nestedifwith list comprehension to find even numbers that are divisible by5. # find even numbers that are divisible by 5num_list = [yforyinrange(100)ify %2==0ify %5==0] print(num_list) Run Code Output [0, 10, 20, 30, 40, 50, 60, 70, 80, 90] ...
if x>5 and x%2==0: print("x is larger than 5 and divisible by 2!") You’re free to choose the one that’s clearer, with the caveat that you must use the same amount of whitespace on either side of the operator.The following isn’t acceptable:Python ❌ Not recommended ...
2. Using for loop To get even numbers from the Python List you can use the for loop to iterate each element in a list and check if it is an even number, if it then add it to a newlist. We are checking if the iterator is divisible by 2 or not to find the even number ...
--可以直接判断某个字符串,然后进行处理-->{% if forloop.counter0|divisibleby:"2" %}<!--使用forloop。counter参数获取遍历的当前数字。counter0是从0开始的索引值,divisibleby:"2"是指能够被2整除-->username:{{user_info.username}},E-mail:{{user_info.email}}{% else %}username:{{user_info....