然后,我们可以使用os.path.isdir()函数来判断这些名称是否是文件夹。 defget_subfolders(directory):subfolders=[]foriteminos.listdir(directory):ifos.path.isdir(os.path.join(directory,item)):subfolders.append(item)returnsubfolders 1. 2
import os def get_subfolders(directory): """ 获取指定目录下的所有子文件夹名称。 :param directory: 要搜索的根目录路径 :return: 子文件夹名称列表 """ subfolders = [] for item in os.listdir(directory): item_path = os.path.join(directory, item) if os.path.isdir(item_path): subfolders.app...
import os def get_subfolders(folder_path): try: subfolders = [f for f in os.listdir(folder_path) if os.path.isdir(os.path.join(folder_path, f))] return subfolders except Exception as e: print(f"Error: {e}") return [] # 调用函数并传递文件夹路径 folder_path = "/path/to/your/fo...
>>> import os >>> >>> for foldername, subfolders, filenames in os.walk('.'): ... print(f'当前目录的路径:{foldername}') ... for subfolder in subfolders: ... print(f'当前目录中子目录的路径:{foldername}/{subfolder}') ... for filename in filenames: ... print(f'当前目录...
就像你可以在代码for i in range(10):中选择变量名i一样,你也可以为前面列出的三个值选择变量名。我通常用foldername、subfolders和filenames这些名字。 当您运行该程序时,它将输出以下内容: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 The current folder isC:\deliciousSUBFOLDEROFC:\delicious:catsSUB...
importosdefget_directory_tree(root):forfolder_path,subfolders,filesinos.walk(root):print("文件夹:",folder_path)forsubfolderinsubfolders:print("子文件夹:",os.path.join(folder_path,subfolder))forfileinfiles:print("文件:",os.path.join(folder_path,file))root_directory="C:/"get_directory_tree...
'Kilobytes':float(1)/1024,'Megabytes':float(1)/(1024*1024),'Gigabytes':float(1)/(1024*1024*1024)}# Walk through all the directories.For each iteration,os.walk returns the folders,subfolders and filesinthe dir.for(path,dirs,files)inos.walk(folder_path):forfileinfiles:# Get all the ...
就像你可以在代码for i in range(10):中选择变量名i一样,你也可以为前面列出的三个值选择变量名。我通常用foldername、subfolders和filenames这些名字。 当您运行该程序时,它将输出以下内容: The current folderisC:\delicious SUBFOLDER OF C:\delicious: cats ...
//get files in current folder & subfolders functionGetFiles(folder, mask) { varresult=newArray(); //do files in current folder varfiles=newEnumerator(folder.Files); for(;!files.atEnd(); files.moveNext()) { if(MatchesMask(files.item(), mask)) { ...
folderName, subfolders, filenames in os.walk('directory'): print('The current folder is ' + folderName) for subfolder in subfolders: print('SUBFOLDER OF ' + folderName + ': ' + subfolder) for filename in filenames: print('FILE INSIDE ' + folderName + ': '+ filename) ...