下面是一个完整的示例代码,演示了如何使用 Python 获取当前目录下的文件夹并打印出来: importosdefget_folders_in_current_directory():folders=[]foriteminos.listdir():ifos.path.isdir(item):folders.append(item)returnfolders folders=get_folders_in_current_directory()print(folders) 1. 2. 3. 4. 5. 6...
1. 完整代码 下面是完整的示例代码,包括上述步骤的实现: importosdefget_folders(path):folders=[]forfile_or_folderinos.listdir(path):ifos.path.isdir(os.path.join(path,file_or_folder)):folders.append(file_or_folder)returnfolders# 测试代码path=os.getcwd()folders=get_folders(path)print(folders) 1...
get_folder_names(full_path, folders) folders = [] get_folder_names('/get/to/path/directory/', folders) print(folders) 上述代码中我们定义了一个递归函数get_folder_names()。该函数可以遍历指定路径下所有子目录,并把文件夹名称保存到folders列表中。执行上述代码将输出指定目录下所有目录层级的文件夹名称...
def extract_folder_names(file_path): folders = file_path.split('/') return [folder for folder in folders if folder] # 示例:解析文件路径并获取每个文件夹的名称 file_path = "/path/to/directory/file.txt" folder_names = extract_folder_names(file_path) print("文件路径中的文件夹名称:", fol...
How do I get the absolute paths of all the files in a directory that could have many sub-folders in Python? I know os.walk() recursively gives me a list of directories and files, but that doesn't seem to get me what I want. ...
blackfolders = {'assets'} # 不打印到index.md的目录集合 blackfiles = {'.DS_Store', 'get_directory_structure.py', 'index.md'} # 不打印到index.md的文件集合 f = Folder(Path("."), 0, blackfolders, blackfiles) outputfile = open("index.md", mode='w') ...
1 python : how to get absolute path for a parent dir 0 Getting the absolute paths of all files in a folder, without traversing the subfolders 1 Return the absolute path to files from different folders 0 Get absolute path of files in sub-directory Hot Network Questions How...
import os # 指定目录路径 directory_path = r'目标路径' # 获取目录下所有文件夹名 folders = [folder for folder in os.listdir(directory_path) if os.path.isdir(os.path.join(directory_path, folder))] # 创建一个空字典,用于存储前5位相同的文件夹名 same_prefix_folders = {} # 遍历文件夹 for...
backup_dir =Folder(config.get_value("backup_dir"), name="Backup Directory") folders = [master_dir, working_dir, server_dir, web_dir, backup_dir] log("Done!")ifconfig.get_flag("no-backup"): command_chain.pop(0) 开发者ID:AugustusLongeye,项目名称:Technic-Script,代码行数:32,代码来源:...
def get_folder_by_path(account, path, is_public=False): # handle exchange folder id if len(path) == 120: folders_map = account.root._folders_map if path in folders_map: return account.root._folders_map[path] if is_public: folder_result = account.public_folders_root elif path == ...