3、获取下周周一、周天的日期 # date: "2022-08-09"defget_next_week(date=None):ifdate:today=datetime.datetime.strptime(str(date),'%Y-%m-%d')else:today=datetime.datetime.today()start_time=today+datetime.timedelta(days=7-today.weekday())end_time=start_time+datetime.timedelta(days=6)returnstar...
import datetime def next_weekday(d, weekday): days_ahead = weekday - d.weekday() if days_ahead <= 0: days_ahead += 7 return d + datetime.timedelta(days_ahead) d = datetime.date(2021, 5, 16) next_sunday = next_weekday(d, 6) print(next_sunday) 1. 2. 3. 4. 5. 6. 7....
def get_next_week(date=None): if date: today = datetime.datetime.strptime(str(date), '%Y-%m-%d') else: today = datetime.datetime.today() start_time = today + datetime.timedelta(days=7-today.weekday()) end_time = start_time + datetime.timedelta(days=6) return start_time.strftime("...
from datetimeimportdatetimeprint(f"星期{list('一二三四五六日')[datetime.today().weekday()]}") 【瑜亮老师】解答 下面这个代码是【瑜亮老师】提供的,如下所示: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 week_dict={1:'星期一',2:'星期二',3:'星期三',4:'星期四',5:'星期五',6:'...
today1+=oneweek#获取下周周日的时间iftoday2.weekday() !=m2: today2+=oneweekwhiletoday2.weekday() !=m2: today2+=onedayelse: today2+=oneweek#转换时间形式nextMonday = today1.strftime('%Y%m%d') nextSunday= today2.strftime('%Y%m%d')#获取下周七天的时间列表date_list = [d.strftime("%Y-...
def get_today(): today = arrow.now() if today.weekday() not in [5, 6]: return today.format('YYYY-MM-DD') def get_next_day(): next_day = arrow.now().shift(days=+1) if next_day.weekday() not in [5, 6]: return next_day.format('YYYY-MM-DD') ...
():返回日期对应的Gregorian Calendar日期;date.weekday():返回weekday,如果是星期一,返回0;如果是星期2,返回1,以此类推;data.isoweekday():返回weekday,如果是星期一,返回1;如果是星期2,返回2,以此类推;date.isocalendar():返回格式如(year,month,day)的元组;date.isoformat():返回格式如'YYYY-MM-DD’的...
如何从weekday和time字符串创建JS Date对象 首先,编写一个代码来解码<day>:<startHours>-<endHours>字符串。然后,你可以这样做 let day = 1; // Mon : 1, Tue: 2, Wed: 3 ...let startHours = 18;let endHours= 20;// get the start of the periodlet dateStart = new Date();dateStart.setD...
WHERE DATEPART(WEEKDAY, GETDATE()) = 2 --Monday Python:从df开始添加星期 您可以使用pandasto_timelta函数将周数列转换为时间增量,如下所示: import pandas as pdimport numpy as np# create a DataFrame with a `date` columndf = pd.DataFrame( pd.date_range(start='1/1/2018', end='1/08/2018...
importdatetime defnext_weekday(d,weekday):days_ahead=weekday-d.weekday()ifdays_ahead<=0:days_ahead+=7returnd+datetime.timedelta(days_ahead)d=datetime.date(2021,5,16)next_sunday=next_weekday(d,6)print(next_sunday) Output: 2021-05-23 ...