def get_current_week(date=None): if date: duty_date = datetime.datetime.strptime(str(date), '%Y-%m-%d') monday, sunday = duty_date, duty_date else: monday, sunday = datetime.date.today(), datetime.date.today() one_day = datetime.timedelta(days=1) while monday.weekday() != 0: ...
以下是使用 calendar 模块获取当前周数的示例代码: importcalendarimportdatetime# 获取当前日期current_date=datetime.date.today()# 获取当前日期的 ISO 8601 标准周数year,week,weekday=calendar.isocalendar(current_date)print("当前日期:",current_date)print("当前年份:",year)print("当前周数:",week)print("...
def get_current_week(): monday, sunday = datetime.date.today(), datetime.date.today() one_day =datetime.timedelta(days=1) while monday.weekday() != 0: monday -= one_day while sunday.weekday() != 6: sunday += one_day monday_datetime = date2datetime(monday) sunday_datetime = date...
importdatetime defget_current_weekday(n):today_info=datetime.date.today()print("今天是:",today_info)today_n=today_info.weekday()day_n=today_info one_day=datetime.timedelta(days=1)iftoday_n<n:whileday_n.weekday()!=n:day_n+=one_dayelse:whileday_n.weekday()!=n:day_n-=one_dayret...
1、获取本周(指定日期)周一、周天的日期 # date: "2022-08-09"defget_current_week(date=None):ifdate:# 使用 datetime.date.fromisoformat 方法将字符串转换为日期对象duty_date=datetime.date.fromisoformat(date)else:duty_date=datetime.date.today()# 使用 isocalendar() 方法直接获取 ISO 年和周数,从而...
_end_time = last_day_of_month(datetime.date.today()).__str__() +' '+'23:59:59'print(_end_time)defget_current_week(): monday, sunday = datetime.date.today(), datetime.date.today() one_day = datetime.timedelta(days=1)whilemonday.weekday() !=0: ...
defget_current_week(): monday, sunday=datetime.date.today(), datetime.date.today() one_day=datetime.timedelta(days=1) whilemonday.weekday() !=0: monday-=one_day whilesunday.weekday() !=6: sunday+=one_day returnstr(monday),str(sunday) ...
timetuple())) 179 180 181 def getCurrentWeekTime(): 182 """ 183 description: 获取本周周一0点184 return: 1557676800 -> str 185 tips: 可替换成: timestamps = time.mktime(time.strptime(time.strftime("%Y-%m-%d", time.localtime(times)), "%Y-%m-%d")) 186 """ 187 week = int(time...
具体方法是使用datetime对象的weekday()方法来获取当前日期是一周中的第几天,然后通过减去对应的天数来得到周日的日期。 以下是一个示例代码: 代码语言:txt 复制 import datetime def get_sunday_of_current_week(): today = datetime.date.today() sunday = today - datetime.timedelta(days=today.weekday()) ...
WHERE DATEPART(WEEKDAY, GETDATE()) = 2 --Monday Python:从df开始添加星期 您可以使用pandasto_timelta函数将周数列转换为时间增量,如下所示: import pandas as pdimport numpy as np# create a DataFrame with a `date` columndf = pd.DataFrame( pd.date_range(start='1/1/2018', end='1/08/2018...