In the second set of curly braces ({}) in the f-string, you use a conditional expression to print dir if the item is a directory, or file if it isn’t. To get this information, you use the .is_dir() method.Putt
RoutedEventArgs e){//string debugPath = System.Environment.CurrentDirectory; //此c#项目的debug文件夹路径string pyexePath=@"C:\Users\user\Desktop\test\dist\main.exe";//python文件所在路径,一般
这样,我们可以遍历目录树的每个子目录,找到所有的文件。 下面是修改后的代码: importosdefget_all_files(directory):all_files=[]forroot,dirs,filesinos.walk(directory):forfileinfiles:file_path=os.path.join(root,file)all_files.append(file_path)forsubdirindirs:subdir_path=os.path.join(root,subdir)al...
data = file.read() num = int(data) except (FileNotFoundError, ValueError) as e: print(f"发生错误:{e}") 1. 2. 3. 4. 5. 6. 3. 通用异常捕获 try: # 复杂操作 result = some_function() except Exception as e: print(f"发生未知错误:{e}") # 建议记录详细错误日志 import traceback ...
("Get all file list.", LOG_INFO_TYPE) devices_files = {} for path in all_devices_paths: device_path_list = get_file_list(path) devices_files.update({path : device_path_list}) return devices_files def get_devices_images_files(files_list, cc_image): """Obtain the system software ...
``` # Python script to rename multiple files in a directory import os def rename_files(directory_path, old_name, new_name): for filename in os.listdir(directory_path): if old_name in filename: new_filename = filename.replace(old_name, new_name) os.rename(os.path.join(directory_path...
,filename])Out[5]:'/home/jeffery0207/a.txt'In[6]:f'{directory}/{filename}'# python3.6之后新增Out[6]:'/home/jeffery0207/a.txt'In[7]:'{0}/{1}'.format(directory,filename)Out[7]:'/home/jeffery0207/a.txt'In[8]:'%s/%s'%(directory,filename)Out[8]:'/home/jeffery0207/a.txt'...
Ecere(简称eC),是加拿大学者jerome历时十二年开发的一门编译型编程语言,拥有C++项目的性能、Java的跨平台性以及Python语法的简洁性。ecere在C语言的基础上加入了面向对象的支持,但与C++、Java相比,它更像是一个C语言的Shell,他将程序员与C之间的复杂性隔离开来,还有
# Gather other propertiesprint("Is a symlink: ", os.path.islink(file_path))print("Absolute Path: ", os.path.abspath(file_path))print("File exists: ", os.path.exists(file_path))print("Parent directory: ", os.path.dirname(file_path))print("Parent directory: {} | File name: {}"....
open("document.docx", "rb") as docx_file: result = mammoth.convert_to_html(docx_file) ...