FloatProcessor- num: float+round_to_two_decimals() : float+format_to_two_decimals() : str+floor_to_two_decimals() : float 旅行图 让我们用一个旅行图的示例来说明使用上述三种方法处理浮点数的过程: 使用round函数 FloatProcessor->FloatProcessor FloatProcessor->FloatProcessor FloatProcessor-->FloatP...
1.function returnFloat(value){},参数是要被转换的数字。 2.var value=Math.round(parseFloat(value)*100)/100,这个应该是函数的核心之处,parseFloat(value)将参数转换为浮点数,因为参数有可能是字符串,乘以100是因为要保留两位小数,先将小数点向右移动两个位数,然后再利用Math.round()方法实行四舍五入计算,最后...
Round to 2 decimal places using the round() function The round() function is Python’s built-in function for rounding float point numbers to the specified number of decimal places. You can specify the number of decimal places to round by providing a value in the second argument. The example...
return Decimal(str(n)).quantize(Decimal(s), rounding=ROUND_HALF_UP) print(round_dec(3.545,2)) # 保留两位小数 def myRound(res): if res=="" or res==0: returnData=0.00 else: if isinstance(res,float): new_res=res*100 returnData=round(new_res)/100 elif isinstance(res,str): new_re...
round()函数可以接受两个参数,第一个参数是要进行截断的浮点数,第二个参数是要保留的小数位数。为了截断浮点数后面的小数,可以将小数部分与整数部分相加后取整数部分。具体实现如下: 代码语言:txt 复制 import math def truncate_float(num, decimal_places): integer_part = int(num) # 获取整数部分 decimal...
但是当出现.5的 时候,两边的距离都⼀样,round()取靠近的偶数,这就是为什么round(2.5) = 2。当指定取舍的⼩数点位数的时候,⼀般情况也是使⽤四 舍五⼊的规则,但是碰到.5的这样情况,如果要取Pythonfloat显示整数位和小数位补零Pythonfloat显⽰整数位和⼩数位补零...
as number.NoteThe behavior of round() for floats can be surprising: for example, round(2.675, 2) gives 2.67 instead of the expected 2.68. This is not a bug: it’s a result of the fact that most decimal fractions can’t be represented exactly as a float....
python2和python3的doc中都举了个相同的例子,原文是这么说的: NoteThebehavior of round()forfloats can be surprising:forexample,round(2.675,2)gives2.67instead of the expected2.68.Thisisnota bug:it’s a result of the fact that mostdecimalfractions can’t be represented exactlyasafloat.SeeFloatingPoi...
Signature: np.around(a, decimals=0, out=None) Docstring: Evenly round to the given number of decimals. 翻译就是:a表示需要保留小数位数的数组或数字,decimals表示要保留的小数位数 In [138]: np.around(3.124, 2) Out[138]: 3.12 In [139]: np.around(3.125, 2) ...
2.68. This is not a bug: it's a result of the fact that most decimal fractions can't be represented exactly as afloat. See Floating Point Arithmetic: Issues and Limitations for more information. 简单的说就是,round(2.675, 2) 的结果,不论我们从python2还是3来看,结果都应该是2.68的,结果它...