For more pleasant output, you may wish to use string formatting to produce a limited number of significant digits: >>> >>>format(math.pi,'.12g')# give 12 significant digits'3.14159265359'>>>format(math.pi,'.2f')# give 2 digits after the point'3.14'>>>repr(math.pi)'3.141592653589793'...
python def sum_decimal_digits(number: float) -> int:# 获取小数部分 decimal_part = str(number)...
/* Larger numbers: loop to determine number of digits */ // 大数,没有限制,根据数字来决定 t = abs_ival; while(t) { ++ndigits;// 需要多少字就申请多少字内存 t >>= PyLong_SHIFT;// 每次右移 15 位,存储为一个字 } v = _PyLong_New(ndigits);// 申请内存 if(v !=NULL) { digit ...
float also accepts the strings “nan” and “inf” with an optional prefix “+” or “-” for Not a Number (NaN) and positive or negative infinity.>>> int(10.9898) 10 >>> int('10.9898') # 解释器抛出 ValueError,并给出基本描述 Traceback (most recent call last): File "<stdin>", ...
string version of everything it displays. For floats, ``repr(float)`` rounds the true decimal value to 17 significant digits, giving : Python 使用内置的 :func:`repr` 函数获取它要显示的每一个对象的字符串版 本。对于浮点数, ``repr(float)`` 将真正的十进制值处理为十七位精度,得 ...
new_number = number_lst[0] + "." + number_lst[1][:n_digits] else: new_number = number_lst[0] + "." + "0" * n_digits else: new_number = number_lst[0] return new_number 1. 2. 3. 4. 5. 6. 7. 8. 9. 10.
1、round(number[, ndigits])用于四舍五入,number是被四舍五入的数,ndigits是小数点后保留的位数。 示例: x = 3.14159 print(round(x, 2)) # 输出: 3.14 # 表示大数 large_number = 1.2e6 # 等同于1.2 * 10**6 print(large_number) # 输出: 1200000.0 ...
number refers to the number to be rounded off. numberOfDigitsPostDecimal refers to the number of digits after the decimal number will be rounded off to. If you don’t provide this argument, you’ll get an integer as the result of round() applied on any float type number. ...
Return the floating point value number rounded to ndigits digits after the decimal point. If ndigits is omitted, it defaults to zero. The result is a floating point number. Values are rounded to the closest multiple of 10 to the power minus ndigits; if two multiples are equally close, ro...
Python has a built-in round() function that takes two numeric arguments, n and ndigits, and returns the number n rounded to ndigits. The ndigits argument defaults to zero, so leaving it out results in a number rounded to an integer. As you’ll see, round() may not work quite as ...