str.find(sub[, start[, end]]) 返回从左开始第一次找到指定子字符串时的索引，找不到就返回 -1...
string = "test test test test" print string.find('test') # 0 print string.rfind('test') # 15 #this is the goal print string.find_all('test') # [0,5,10,15] For counting the occurrences, see Count number of occurrences of a substring in a string. python string Share Improve th...
Return the number of non-overlapping(不覆盖) occurrences(发生) of substring(子字符串) sub in string S[start:end]. Optional arguments start and end are interpreted(解释的) as in slice(默认) notation(符号). """ str2 = "hello world!" print(str2.count("l")) # 3 print(str2.count("l...
| Raises ValueError when the substring is not found. | | isalnum(self, /) | Return True if the string is an alpha-numeric string, False otherwise. | | A string is alpha-numeric if all characters in the string are alpha-numeric and | there is at least one character in the string. |...
| done using the specified fill character (default is a space) | | count(...) | S.count(sub[, start[, end]]) - > int | | Return the number of non - overlapping occurrences of substring sub in | string S[start:end]. Optional arguments start and end are interpreted ...
python没有substring函数,因为直接使用str[start:end]就可以啦。字母处理 全部大写:str.upper()全部小写:str.lower()大小写互换:str.swapcase()首字母大写,其余小写:str.capitalize()首字母大写:str.title()print '%s lower=%s' % (str,str.lower())...
Padding is done using the specified fill character (default is a space) """ return "" def count(self, sub, start=None, end=None): """ 子序列个数 """ """ S.count(sub[, start[, end]]) -> int Return the number of non-overlapping occurrences of substring sub in string S[start...
Return the number of non-overlapping(不覆盖) occurrences(发生) of substring(子字符串) sub in string S[start:end]. Optional arguments start and end are interpreted(解释的) as in slice(默认) notation(符号)."""str2="hello world!"print(str2.count("l"))#3print(str2.count("l", 3))#...
For those who don't know, you can create any substring from azString using the notation azString[x:y] Coming from other programming languages, that's when the common sense gets compromised. What are x and y? I had to sit down and run several scenarios in my quest for a memorization ...
space) 24 """ 25 return "" 26 27 def count(self, sub, start=None, end=None): # real signature unknown; restored from __doc__ 28 """ 29 S.count(sub[, start[, end]]) -> int 30 31 Return the number of non-overlapping occurrences of substring sub in 32 string S[start:end]...