参考资料:https://www.geeksforgeeks.org/python-finding-strings-with-given-substring-in-list/ 方法1: In [1]: data=["北京市","福建省","河南省","杭州市"] In [2]: word="福建" In [3]: [iforiindataifwordini] Out[3]: ['福建省'] 方法2: In [4]: data=["北京市","福建省","...
we have to call it on the string that’ll be used for joining. In this case, we’re using a string with a space in it. The method receives a list of strings and returns one string with each of the strings joined by the initial string. Let’s check its functionality with...
split(s, sep=None, maxsplit=-1) split(s [,sep [,maxsplit]]) -> list of strings 使用sep为分隔符,从左边开始分割字符串,最大分割次数为maxslit。默认分割符为空格,全部分割。 splitfields = split(s, sep=None, maxsplit=-1) split(s [,sep [,maxsplit]]) -> list of strings 用法和split...
If tabsize is not given, a tab size of 8 characters is assumed. """ return "" def find(self, sub, start=None, end=None): """ 寻找子序列位置,如果没找到,返回 -1 """ """ S.find(sub [,start [,end]]) -> int Return the lowest index in S where substring sub is found, such...
have good taste in clothes. The substring to find: good The start indices of the substrings ...
print('Substring count =', s.count('Th')) Output: Find all indexes of substring There is no built-in function to get the list of all the indexes for the substring. However, we can easily define one using find() function. def find_all_indexes(input_str, substring): ...
s.find('peach')# 返回第一次出现的位置 1. 7 1. Docstring: S.find(sub[, start[, end]]) -> int Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. ...
语法:str.rsplit(sep=None, maxsplit=-1) -> list of strings 返回 字符串列表 或str.rsplit(sep=None, maxsplit=-1)[n] 参数: sep —— 分隔符,默认为空格,但不能为空即(")。 maxsplit —— 最大分割参数,默认参数为-1。 [n] —— 返回列表中下标为n的元素。列表索引的用法。
File "", line 1, in <module> ValueError: substring not found >>> str.index("n") #同find类似,返回第一次匹配的索引值 4 >>> str.rindex("n") #返回最后一次匹配的索引值 11 >>> str.count('a') #字符串中匹配的次数 0 >>> str.count('n') #同上 2 >>> str.replace('EAR','ear...
str.find() 查找 代码语言:javascript 代码运行次数:0 运行 AI代码解释 In [90]: help(s1.find) Help on built-in function find: find(...) S.find(sub [,start [,end]]) -> int Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]...