def find_substring_in(s, sub):""" 使用in关键字查找子字符串 """if sub in s:return Trueelse:return False# 定义一个字符串string = 'A New String Hello, World!'sub_string = "Hello"print('例1，源字符串为：', string, ' 待查找字符串
S.find(substring, [start [,end]]) #可指范围查找子串,返回索引值,否则返回-1 S.rfind(substring,[start [,end]]) #反向查找 S.index(substring,[start [,end]]) #同find,只是找不到产生ValueError异常 S.rindex(substring,[start [,end]])#同上反向查找 S.count(substring,[start [,end]]) #返回...
string_id INT contents VARCHAR } SUBSTRING { substring_id INT contents VARCHAR } STRING ||--|| SUBSTRING 在关系图中,STRING表表示字符串,包含string_id和contents字段;SUBSTRING表表示子串,包含substring_id和contents字段;STRING和SUBSTRING之间存在一对一的关系。 通过本文的介绍,相信读者已经了解了如何在Python...
substring="python"string="welcome to pythontip"print(substringinstring) 如果存在,则返回True,否则返回False。此处,输出为True。 如何检查子字符串是否存在-另一种方法 你也可以使用find()方法检查字符串中是否存在子字符串。 如下示例: substring="zz"string="hello world"print(string.find(substring)) 如果存在...
如果字符串中存在子字符串,则 in 运算符将返回 True,否则返回 False。这是一个例子: # The string string = 'Hello World, this is a string' # substring substring = 'this' if substring in string: print('Found the substring!') else: print('Could not find the substring.') 使用index() 方法...
Python 字符串直接在方括号([])中使用索引即可获取对应的字符,其基本语法格式为:string[index] 这里的 string 表示要截取的字符串,index 表示索引值。 【例1】s = 'crazyit.org is very good' # 获取s中索引2处的字符 print(s[2]) # 输出a
In the case of Loops, it was used for iteration, whereas in this case it’s a conditional that can be eithertrueorfalse.It’ll be true if the substring is part of the string, and false if it’s not. 3. Transforming Strings
substring2 =string[:-3] print(substring2) # Print"The quick brown " 获取字符串中的一个字符 这个很简单,如果切片中没有:字符,只包含数字,它将返回该索引处的字符。 例子: string='0123456789' substring =string[4] print(substring) # Print "4" ...
print(quote.find('o small ',10,-1)) # Substring is searched in 'll things with'print(quote.find('things ',6,20)) Run Code Output -1 3 -1 9 Also Read: Python String index() Python String count()
Python String find() The find() method returns the lowest index of the substring if it is found in given string. If its is not found then it returns -1. Syntax : str.find(sub,start,end) Parameters : sub :It’s the substring which needs to be searched in the given string....