def find_substring(substring, lst): return [string for string in lst if substring in string] 这个方法使用列表推导式,将满足条件的字符串添加到结果列表中。 使用filter函数和lambda表达式: 代码语言:txt 复制 def find_substring(substring, lst): return list(filter(lambda string: substring in string, ls...
find(substring):查找字符串中是否包含指定的substring,返回第一个匹配的索引值。 index(substring):查找字符串中是否包含指定的substring,返回第一个匹配的索引值,如果没有找到则抛出异常。 以下是对每种方法的代码示例: forstringinstrings:ifstring.startswith("a"):# 匹配以"a"开头的字符串print(string)ifstring...
class StringHelper{ + find(substring: str): int + rfind(substring: str): int } class RegexHelper{ + find_all_positions(substring: str, string: str): list } class ListHelper{ + find_all_positions(substring: str, string: str): list } StringHelper <|-- RegexHelper StringHelper <|-- Lis...
In order to avoid thisTraceback Error, we can use the keywordinto check if a substring is contained in a string. In the case of Loops, it was used for iteration, whereas in this case it’s a conditional that can be eithertrueorfalse.It’ll be true if the substring is part of the ...
string is: This dress looks good; you have good taste in clothes. The substring to find: good...
(1) list 普通的链表,初始化后可以通过特定方法动态增加元素。 定义方式:arr = [元素] (2) Tuple 固定的数组,一旦定义后,其元素个数是不能再改变的。 定义方式:arr = (元素) (2) Dictionary 词典类型, 即是Hash数组。 定义方式:arr = {元素k:v} ...
Python index() 方法检测字符串中是否包含子字符串 str ,如果指定 beg(开始) 和 end(结束) 范围,则检查是否包含在指定范围内,该方法与 python find()方法一样,只不过如果str不在 string中会报一个异常。语法index()方法语法:str.index(substring, beg=0, end=len(string))...
ValueError: substring not fou 16、rindex() 描述:rindex() 方法返回子字符串最后一次出现在字符串中的索引位置,该方法与rfind()方法一样,可以规定字符串的索引查找范围[star,end),只不过如果子字符串不在字符串中会报一个异常。 语法:str.rindex(sub, start, end) -> int 返回整数。
str.find() 查找 代码语言:javascript 代码运行次数:0 运行 AI代码解释 In [90]: help(s1.find) Help on built-in function find: find(...) S.find(sub [,start [,end]]) -> int Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]...
6.find()方法 ''' find() 方法:S.find(sub[, start[, end]]) -> int Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. ...