参考资料:https://www.geeksforgeeks.org/python-finding-strings-with-given-substring-in-list/ 方法1: In [1]: data=["北京市","福建省","河南省","杭州市"] In [2]: word="福建" In [3]: [iforiindataifwordini] Out[3]: ['福建省'] 方法2: In [4]: data=["北京市","福建省","...
However, there’s a better way to identify which cells in a column contain a substring: you’ll usepandas! In this example, you’ll work with a CSV file that contains fake company names and slogans. You can download the file below if you want to work along: ...
This tutorial will introduce how to find elements from a Python list that have a specific substring in them. We will work with the following list and extract strings that haveackin them. my_list=["Jack","Mack","Jay","Mark"] Use theforLoop to Find Elements From a List That Contain a...
Naturally, it performs the same search as index() and returns the index of the start of the substring within the parent string: print(fullstring.find(substring)) # 1 Regular Expressions (RegEx) Regular expressions provide a more flexible (albeit more complex) way to check strings for pattern...
string="Hello, World!"substrings=["Hello","World"]ifall(substringinstringforsubstringinsubstrings):print("字符串包含多个字符")else:print("字符串不包含多个字符") 1. 2. 3. 4. 5. 6. 以上是几种常见的方法,用于判断一个字符串是否包含多个字符的问题。根据实际情况选择合适的方法,以提高代码的可读...
string="This is a test string."substring="is"positions=find_all_substrings(string,substring)print(positions) 1. 2. 3. 4. 运行上述代码,将输出:[2, 5],表示在给定的字符串中,子串"is"出现在位置2和位置5。 结束 到此为止,我们已经完成了查找所有子串的性能。希望这篇文章对你有所帮助,让你更好地...
str.find(sub[, start[, end]]) Return the lowest index in the string where substring sub is found, such that sub is contained in the slice s[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 if sub is not found.Note: The find() method sho...
string="Python Programming"substring=string[7:14]# 从索引7开始至索引14前结束print(substring)# 输出:"Programming"# 切片步长为-1,反转字符串reversed_substring=string[::-1]print(reversed_substring)# 输出:"gnimmargorP nohtyP" 2.2 高级字符串操作 ...
str.find(sub[, start[, end]])在字符串中查找sub,找到后返回位置,没找到返回-1. Return the lowest index in the string where substring sub is found, such that sub is contained in the range [start, end]. Optional arguments start and end are interpreted as in slice notation. Return -1 if...
There is no index that satisfies the conditions in the problem statement. Example 3: Input: nums = [2,1,-1] Output: 0 Explanation: The pivot index is 0. Left sum = 0 (no elements to the left of index 0) Right sum = nums[1] + nums[2] = 1 + -1 = 0 ...