最大公因数(Greatest Common Divisor,简称GCD)是指能够同时整除给定两个或多个整数的最大正整数。计算最大公因数的常用方法有欧几里得算法(辗转相除法)和更相减损术。本文将使用欧几里得算法来计算最大公因数。 欧几里得算法 欧几里得算法的思想是通过反复用较小的数除较大的数,直到余数为0为止。其中,最后的除数就是...
# Define a function to calculate the greatest common divisor (GCD) of two numbers.defgcd(x,y):# Initialize z as the remainder of x divided by y.z=x%y# Use a while loop to find the GCD.whilez:# Update x to y, y to z, and calculate a new value for z (remainder of x divided...
class Solution: def dividable(self, s, divisor): div_len = len(divisor) s_len = len(s) if s_len % div_len != 0: return False n = s_len // div_len if divisor * n == s: return True return False def gcdOfStrings(self, str1: str, str2: str) -> str: s1_len = len(...
The highest common factor (H.C.F) or greatest common divisor (G.C.D) of two numbers is the largest positive integer that perfectly divides the two given numbers. For example, the H.C.F of 12 and 14 is 2. Source Code: Using Loops # Python program to find H.C.F of two numbers#...
return find_GCD int1 = int(input("Input 1st integer: ")) int2 = int(input("Input 2nd integer: ")) print("The greatest common divisor of {} and {} is {}".format(int1, int2, find_GCD(int1, int2))) 代码运行结果如下:
LeetCode 1071. Greatest Common Divisor of Strings字符串的最大公因子【Easy】【Python】【字符串】 Problem LeetCode For stringsSandT, we say "TdividesS" if and only ifS = T + ... + T(Tconcatenated with itself 1 or more times)
email elford@foxmail.com # === import random # Find the greatest common divisor def gcd(a, b): if a < b: return gcd(b, a) elif a % b == 0: return b else: return gcd(b, a % b) # Quick power & modulo def power(a, b, c): ans = 1 while b != 0: if b & 1:...
Find the greatest common divisor of the two integers: #Import math Library importmath #find the the greatest common divisor of the two integers print(math.gcd(3,6)) print(math.gcd(6,12)) print(math.gcd(12,36)) print(math.gcd(-12, -36)) ...
题目地址:https://leetcode.com/problems/greatest-common-divisor-of-strings/题目描述For strings S and T, we say "T divides S" if and only if S = T + ... + T (T concatenated with itself 1 or more times)Return the largest string X such that X divides str1 and X divides str2....
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