LeetCode 1071. Greatest Common Divisor of Strings字符串的最大公因子【Easy】【Python】【字符串】 Problem LeetCode For stringsSandT, we say "TdividesS" if and only ifS = T + ... + T(Tconcatenated with itself 1 or more times) Return the largest stringXsuch thatXdivides str1 andXdivides...
https://leetcode.com/problems/greatest-common-divisor-of-strings/discuss/307242/C%2B%2B-3-lines https://leetcode.com/problems/greatest-common-divisor-of-strings/discuss/303759/My-4-Lines-C%2B%2B-Solution https://leetcode.com/problems/greatest-common-divisor-of-strings/discuss/303781/JavaPython...
Greatest Common Divisor of Strings 解题报告(Python & C++) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力遍历 日期 题目地址:https://leetcode.com/problems/greatest-common-divisor-of-strings/ 题目描述 For strings S and T, we say "T...
For two strings s and t, we say “t divides s” if and only if s = t + … + t (t concatenated with itself 1 or more times) Given two strings str1 and str2, return the largest string x such that x divides both str1 and str2. Example 1: AI检测代码解析 Input: str1 = "AB...
Greatest Common Divisor of Strings (Java版; Easy) welcome to my blog LeetCode 1071. Greatest Common Divisor of Strings (Java版; Easy) 题目描述 第一次做; 暴力; 核心:1)如果两个字符串str1和str2的最大公因字符串是s, 设该字符串长度为n, 那么str1.substring(0,n)一定等于s, str2.substring...
Simple Java program to find GCD (Greatest Common Divisor) or GCF(Greatest Common Factor) or HCF (Highest common factor). The GCD of two numbers is the largest positive integer that divides both the numbers fully i.e. without any remainder. There are multiple methods to find GCD, GDF, or...
题目地址:https://leetcode.com/problems/greatest-common-divisor-of-strings/题目描述For strings S and T, we say "T divides S" if and only if S = T + ... + T (T concatenated with itself 1 or more times)Return the largest string X such that X divides str1 and X divides str2....
代码如下: classSolution(object):defgcdOfStrings(self, str1, str2):""":type str1: str :type str2: str :rtype: str"""foriinrange(len(str1),0,-1):iflen(str1) % i == 0andlen(str2) % i == 0and\ str1[:i]* (len(str1) / i ) == str1andstr1[:i] * (len(str2)...
Greatest Common Divisor of Strings (Java版; Easy) welcome to my blog LeetCode 1071. Greatest Common Divisor of Strings (Java版; Easy) 题目描述 第一次做; 暴力; 核心:1)如果两个字符串str1和str2的最大公因字符串是s, 设该字符串长度为n, 那么str1.substring(0,n)一定等于s, str2.substring...
Greatest Common Divisor of Strings (Java版; Easy) welcome to my blog LeetCode 1071. Greatest Common Divisor of Strings (Java版; Easy) 题目描述 第一次做; 暴力; 核心:1)如果两个字符串str1和str2的最大公因字符串是s, 设该字符串长度为n, 那么str1.substring(0,n)一定等于s, str2.substring...