def find_divisors(n): if n <= 0: raise ValueError("Number must be positive") return [i for i in range(1, n + 1) if n % i == 0] try: number = int(input("Enter a positive integer: ")) print(f"The divisors of {number} are: {find_divisors(number)}") except ValueError as...
return divisors if n % divisor == 0: divisors.append(divisor) return find_divisors(n, divisor + 1, divisors) number = 28 print(f"The divisors of {number} are: {find_divisors(number)}") 在这段代码中,我们定义了一个递归函数find_divisors,它接收三个参数:n是我们要找约数的数,divisor是当前...
下面是一个简单的Python函数,用来求一个数的所有约数: deffind_divisors(num):divisors=[]foriinrange(1,num+1):ifnum%i==0:divisors.append(i)returndivisors number=12result=find_divisors(number)print(f"The divisors of{number}are:{result}") 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 在这段代...
Write a Python program to find the missing digits in a numeric ID that should contain all digits from 0 to 9. Go to: Python Basic Exercises Home ↩ Python Exercises Home ↩ Previous:Write a Python program to find the number of divisors of a given integer is even or odd. Next:Write...
('z 是最小的')py **Finger exercise:** Write a program that examines three variables—`x`, `y`, and `z`—and prints the largest odd number among them. If none of them are odd, it should print the smallest value of the three. You can attack this exercise in a number of ways. ...
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11. Check if a Number is Perfect Write a Python function to check whether a number is "Perfect" or not. According to Wikipedia : In number theory, a perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisor...
The divisors of a number are an important property that has applications in cryptography and other areas. Python has had a function for calculating the greatest common divisor (GCD) of two numbers for a long time: Python >>> import math >>> math.gcd(49, 14) 7 The GCD of 49 and ...
(k) sum += k # Can use += to avoid repetition, and k is an int already # Return the sum of all divisors of n, not including n return sum 如果print纯粹用于调试,并且可以删除,这将简化为one-liner,使用优化的sum函数+生成器表达式: def sum_divisors(n): return sum(k for k in range(...
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