# 获取用户输入user_input=input("请输入一个小数: ")# 提示用户输入一个小数# 将用户输入赋值给一个变量decimal_string=str(user_input)# 保持输入为字符串类型# 查找小数点的位置decimal_point_index=decimal_string.find('.')# 查找小数点# 计算小数的位数ifdecimal_point_index!=-1:# 如果小数点存在decim...
在这一步中,我们需要确定小数点的位置,以便在后续步骤中补0。我们可以使用字符串的find()方法来查找小数点的索引位置。代码如下所示: decimal_index=number_str.find('.') 1. 步骤4:补足小数点后的0 现在,我们已经确定了小数点的位置,我们可以使用字符串的ljust()方法来补足小数点后的0。ljust()方法接受两个...
如果相等,则说明Decimal以该值结尾,否则不以该值结尾。 下面是一个示例代码: 代码语言:txt 复制 def decimal_ends_with(decimal_value, target_value): truncated_decimal = decimal_value.quantize(decimal.Decimal('1.00')) return str(truncated_decimal)[-len(target_value):] == str(target_value) # ...
Strings can beconcatenatedto build longer strings using the plus sign and also they can bemultipliedby a number, which results in the continuous repetition of the string as many times as the number indicates. Also, if we want to find out thelengthof the string, we simply have to use thelen...
1、Numpy 2、Pandas 3、Matplotlib 4、Seaborn 5、Pyecharts 6、wordcloud 7、Faker 8、PySimpleGUI ...
(models.Model): """商品价格表,通过外键关联商品信息表""" price = models.DecimalField(max_digits=10, decimal_places=2, default=0, verbose_name='售价') goods = models.ForeignKey(to='Goods', related_name='goods_price', on_delete=models.SET_NULL, blank=True, null=True,verbose_name='商品...
This means that the number is displayed with exactly two decimal places, even if the original number has fewer decimal places.When n = 7.125, the result of {n:.2f} is 7.12. Just like with round(), Python rounds ties to even when formatting numbers inside strings. So, if you replace ...
BeautifulSoup（爬虫）Tkinter（UI界面）argparse（命令行）math（数学运算）至于其他的，就是因人而异，不...
Return the amount each friend has to pay, rounded off to two decimal places. Check Code Video: Operators in Python Previous Tutorial: Python Basic Input and Output Next Tutorial: Python if...else Statement Share on: Did you find this article helpful?Our...
Challenge: Write a function to compute the area of a circle rounded off to two decimal places. The area of a circle is calculated using the formulapi * radius^2. For example, ifradius = 5, the expected output is78.54. (radius):