# initializing listtest_list = [1,3,5,6,3,5,6,1]print("The original list is : "+ str(test_list)) # using naive method to remove duplicated from listres = []foriintest_list:ifinotinres:res.append(i) # printing list after ...
if i not in res: res.append(i) # printing list after removal print ("The list after removing duplicates : " + str(res)) → 输出结果: The original list is : [1, 3, 5, 6, 3, 5, 6, 1]The list after removing duplicates : [...
def find_duplicates(lst): duplicates = [] seen = set() for item in lst: if item in seen: duplicates.append(item) else: seen.add(item) return duplicates # 示例用法 my_lst = [1, 2, 3, 4, 3, 2, 1, 5] result = find_duplicates(my_lst) print(result) # 输出 [1, 2, 3] 复...
new_list = remove_duplicates(my_list)print(new_list) 代码解析: 首先定义了一个名为remove_duplicates的函数,该函数接受一个列表作为参数,并使用列表推导式生成一个新列表。 列表推导式的语法为[expression for item in iterable if condition]。在这里,我们使用了if x not in lst[:i]来过滤掉重复的元素。
利用pandas库的drop_duplicates()方法去除DataFrame中的重复行 drop_duplicates()方法可以帮助我们去除DataFrame中重复的行，并返回一个新的DataFrame。示例代码：import pandas as pdmy_data = {'col1': [1, 2, 2, 3, 4, 4, 5], 'col2': ['a', 'b', 'b', 'c', 'd', 'd', 'e']}df = ...
Remove duplicates from a list in Python Trey Hunner 3 min. read • Python 3.9—3.13 • March 8, 2023 Share Tags Data Structures Need to de-duplicate a list of items?>>> all_colors = ["blue", "purple", "green", "red", "green", "pink", "blue"] ...
if i not in temp_list: temp_list.append(i) my_list = temp_list print("List After removing duplicates ", my_list) 输出: List Before [1, 2, 3, 1, 2, 4, 5, 4, 6, 2] List After removing duplicates [1, 2, 3, 4, 5, 6] ...
print(unique_list)# 输出: [1, 2, 3, 4, 5] 执行以上代码输出结果为: [1,2,3,4,5] 使用列表推导式 列表推导式结合条件判断也可以实现去重功能。 实例 # 使用列表推导式去重 defremove_duplicates(lst): unique_list=[] [unique_list.append(item)foriteminlstifitemnotinunique_list] ...
importpandasaspd# 创建一个包含重复数据的DataFramedata={'numbers':[1,2,2,3,4,4,5]}df=pd.DataFrame(data)# 使用drop_duplicates()去重unique_df=df.drop_duplicates()print(unique_df)# 输出:# numbers# 0 1# 1 2# 3 3# 4 4# 6 5 ...
def find_duplicates(lst): duplicates = [] for item in lst: if lst.count(item) > 1 and item not in duplicates: duplicates.append(item) return duplicates # 示例用法 my_list = [1, 2, 3, 4, 2, 3, 5] print(find_duplicates(my_list)) # 输出: [2, 3] 复制代码...