可以使用Python的集合(Set)和列表(List)的特性来找出列表中的重复数据。以下是一种常见的方法: deffind_duplicates(lst):duplicates=[]unique_items=set()foriteminlst:ifiteminunique_items:duplicates.append(item)else:unique_items.add(item)returnduplicates# 示例用法my_list=[1,2,3,4,5,2,3,4]result=...
def find_duplicates(lst): return list(set([x for x in lst if lst.count(x) > 1])) # 示例用法 my_list = [1, 2, 3, 4, 2, 3, 5, 6, 1] result = find_duplicates(my_list) print(result) # 输出: [1, 2, 3] 这种方法使用列表推导式和集合来筛选出重复元素。首先,使用列表推导式...
def find_duplicates(lst): counter = Counter(lst) duplicates = [elem for elem, count in counter.items() if count > 1] return duplicates # 测试示例 my_list = [1, 2, 2, 3, 3, 3, 4, 4, 5] duplicate_elements = find_duplicates(my_list) print("列表中的重复元素为:", duplicate_ele...
def find_duplicates(lst): duplicates = [] seen = set() for item in lst: if item in seen: duplicates.append(item) else: seen.add(item) return duplicates # 示例用法 my_lst = [1, 2, 3, 4, 3, 2, 1, 5] result = find_duplicates(my_lst) print(result) # 输出 [1, 2, 3] 复...
return list(duplicates)lst = [1, 2, 2, 3, 4, 4, 5, 6, 6, 6] print(find_duplicates(lst)) # 输出: ``` 方法2:使用collections.Counter 📊```python from collections import Counterdef find_duplicates(lst): counter = Counter(lst) return [item for item, count in counter.items() ...
首先,我们需要编写函数来查找list中的重复元素。代码如下所示: deffind_duplicates(lst):duplicates=[]foriteminlst:iflst.count(item)>1anditemnotinduplicates:duplicates.append(item)returnduplicates 1. 2. 3. 4. 5. 6. 这段代码中,我们定义了一个find_duplicates函数,接受一个list作为参数。然后我们使用for...
接下来,我们将实现DuplicatesFinder类的具体代码。代码示例如下: AI检测代码解析 classDuplicatesFinder:def__init__(self,items):self.items=itemsdeffind_duplicates(self):seen=set()duplicates=set()foriteminself.items:ifiteminseen:duplicates.add(item)else:seen.add(item)returnlist(duplicates)# 示例用法if_...
def find_duplicate_characters_set(input_string): unique_chars = set() duplicates = set() for char in input_string: if char in unique_chars: duplicates.add(char) else: unique_chars.add(char) return list(duplicates) input_str = "hello world" ...
pythonCopy code def find_duplicates(lst): return set([x for x in lst if lst.count...
found:{full_path}=={hashes[file_hash]}")else:hashes[file_hash]=full_pathfind_duplicates('E...