Average Value of Even Numbers That Are Divisible by Three: https://leetcode.com/problems/average-value-of-even-numbers-that-are-divisible-by-three/ 可被三整除的偶数的平均值: https://leetcode.cn/problems/average-value-of-even-numbers-that-are-divisible-by-three/ LeetCode 日更第310天,感谢...
接下来,我们将编写代码,生成一个饼状图,展示1到10中的数字,分为能被3整除和不能被3整除两类。 AI检测代码解析 importmatplotlib.pyplotasplt# 数据准备can_divide_by_3=sum(1fornumintest_numbersifis_divisible_by_3(num))cannot_divide_by_3=len(test_numbers)-can_divide_by_3 sizes=[can_divide_by_...
执行上述代码时,结果如下: enter number8 divisible by 2 not divisible by 3 enter number15 divisible by 3 not divisible by 2 enter number12 Divisible by 3 and 2 enter number5 not Divisible by 2 not divisible by 3 Python 3 条件语句 Python 3 IF...ELIF...ELSE 语句 查看...
# 定义一个空列表用于存放能被3整除的数divisible_by_3=[]# 使用循环遍历1到100之间的所有数fornuminrange(1,101):# 判断当前数是否能被3整除ifnum%3==0:# 将能被3整除的数添加到列表中divisible_by_3.append(num)# 输出结果print("100以内能被3整除的数为:",divisible_by_3) 1. 2. 3. 4. 5....
对else也一样,也就是print(f"This is when n is not divisible by 3 {walk(2*n-1, count - 1}")。 因此,我得到了结果This is when n is not divisible by 3 23.0 This is when n is not divisible by 3 11.0 This is when n is divisible by 3 5.0 15 ...
answer[i] == "Fizz" if i is divisible by 3. answer[i] == "Buzz" if i is divisible by 5. answer[i] == i (as a string) if none of the above conditions are true. 解释一下题目(可以不看) input是一个int整数num,output是这个整数长度的列表,列表第i个元素如果只能够被3整除就是“Fiz...
2 multiplied, the value is 8. Divisible is simple, 10 divided by 3 can not be divided, 10 will be reduced by 1, and then judge whether it can be divided by 3, can not be reduced by 1, until it is divided, the value after division is the result. So 10 // 3 is equal to 3...
# Manually raising a ValueError exception# Accepts an integer argumentdefdivide_by_three(x):# if the argument is divisible by threeifx%3!=0:# If not, raise a ValueError exceptionraiseValueError("Not divisible by three")# Return the result of the divisionreturnx/3# Call the function with ...
Here, the list comprehension will first check to see if the numberxis divisible by 3, and then check to see ifxis divisible by 5. Ifxsatisfies both requirements it will print, and the output is: Output [0, 15, 30, 45, 60, 75, 90] ...
division and returns the remainder of that division. For example, ifx = 3andy = 2, thenx%ywill divide3by2and give us1as a remainder. Thedivisible()function in the following code snippet shows us how we can check whether one number is completely divisible by another number with the%operator...