接下来,我们将编写代码,生成一个饼状图,展示1到10中的数字,分为能被3整除和不能被3整除两类。 AI检测代码解析 importmatplotlib.pyplotasplt# 数据准备can_divide_by_3=sum(1fornumintest_numbersifis_divisible_by_3(num))cannot_divide_by_3=len(test_numbers)-can_divide_by_3 sizes=[can_divide_by_...
执行上述代码时,结果如下: enter number8 divisible by 2 not divisible by 3 enter number15 divisible by 3 not divisible by 2 enter number12 Divisible by 3 and 2 enter number5 not Divisible by 2 not divisible by 3 Python 3 条件语句 Python 3 IF...ELIF...ELSE 语句 查看...
将上述所有代码整合到一起,我们可以得到完整的程序如下: # 获取用户输入的数,使用int()将输入转换为整数number=int(input("请输入一个数字: "))# 检查数字能否被3整除is_divisible_by_3=number%3==0# 如果能够整除,返回True,否则返回False# 检查数字能否被5整除is_divisible_by_5=number%5==0# 如果能够整...
我没有返回函数,而是print(f"This is when n is divisible by 3 {walk(n/3, count - 1)}") 对else也一样,也就是print(f"This is when n is not divisible by 3 {walk(2*n-1, count - 1}")。 因此,我得到了结果This is when n is not divisible by 3 23.0 This is when n is not div...
answer[i] == "Fizz" if i is divisible by 3. answer[i] == "Buzz" if i is divisible by 5. answer[i] == i (as a string) if none of the above conditions are true. 解释一下题目(可以不看) input是一个int整数num,output是这个整数长度的列表,列表第i个元素如果只能够被3整除就是“Fiz...
2 multiplied, the value is 8. Divisible is simple, 10 divided by 3 can not be divided, 10 will be reduced by 1, and then judge whether it can be divided by 3, can not be reduced by 1, until it is divided, the value after division is the result. So 10 // 3 is equal to 3...
Here, the list comprehension will first check to see if the numberxis divisible by 3, and then check to see ifxis divisible by 5. Ifxsatisfies both requirements it will print, and the output is: Output [0, 15, 30, 45, 60, 75, 90] ...
# Manually raising a ValueError exception# Accepts an integer argumentdefdivide_by_three(x):# if the argument is divisible by threeifx%3!=0:# If not, raise a ValueError exceptionraiseValueError("Not divisible by three")# Return the result of the divisionreturnx/3# Call the function with ...
void function fizzbuzz For (i = 1; i <= 100; i++) { set print_number to true; If i is divisible by 3 print "Fizz"; set print_number to false; If i is divisible by 5 print "Buzz"; set print_number to false; If print_number, print i; print a newline; } 请注意大括号...
Print "FizzBuzz" for numbers divisible by both 3 and 5. Print the number itself if it is not divisible by either 3 or 5. 4.What are some common mistakes to avoid when solving the FizzBuzz problem? Common mistakes include: Forgot to check the condition for "FizzBuzz" (multiples of both...