# 创建一个空列表来存储相同的键duplicate_keys=[]# 遍历字典的键forkeyinmy_dict:# 如果键已经存在于列表中,则为相同的键ifkeyinduplicate_keys:print(f"Duplicated key:{key}")else:# 将键添加到列表中duplicate_keys.append(key) 1. 2. 3. 4. 5. 6. 7. 8
duplicate_keys=[]forkeyinmy_dict.keys():iflist(my_dict.keys()).count(key)>1:duplicate_keys.append(key) 1. 2. 3. 4. 3.4 打印出所有相同的键 现在,我们已经确定了存在相同的键,并将它们存储在了duplicate_keys列表中。接下来,我们可以使用一个for循环遍历duplicate_keys列表,并打印出每一个重复的...
Duplicate values will overwrite existing values: thisdict ={ "brand":"Ford", "model":"Mustang", "year":1964, "year":2020 } print(thisdict) Try it Yourself » Dictionary Length To determine how many items a dictionary has, use thelen()function: ...
python-找出字典dic中重复值 # Python code to demonstrate# finding duplicate values from dictionary# initialising dictionaryini_dict = {'a':1,'b':2,'c':3,'d':2}# printing initial_dictionaryprint("initial_dictionary",str(ini_dict))# finding duplicate values# from dictionary using flipflipped ...
def dict_compare(d1, d2): return d1.keys() == d2.keys() and all(d1[k] == d2[k] for k in d1) def remove_duplicate_dicts(dict_list): seen = [] for d in dict_list: if not any(dict_compare(d, seen_d) for seen_d in seen): seen.append(d) return seen # 示例使用...
You can start by creating an empty dictionary, which is specified by empty curly braces. Then you can add new keys and values one at a time: >>>person={} #注意,这个大括号被字典霸占了,set不能用>>>type(person)<class 'dict'>#增加键值对儿>>>person['fname']='Joe'>>>person['lname...
mylist = list(dict.fromkeys(mylist)) print(mylist) Create a dictionary, using the List items as keys. This will automatically remove any duplicates because dictionaries cannot have duplicate keys. Create a Dictionary mylist = ["a","b","a","c","c"] ...
myDict = { 'name' : 'Python User', 'value' : 75 } #This is a dictionary with keys representing # Name and Value Everything after the # on a line is not interpreted by Python, but is instead considered to be a comment from the author about how a reader would interpret the informat...
dict1={"name":"Joy","age":25}dict2={"name":"Joy","city":"New York"}dict3=Merge(dict1,dict2)print(dict3) 输出: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 {'name':'Joy','age':25,'city':'New York'} 2、链式比较 ...
def list_to_dictionary(keys, values): return dict(zip(keys, values)) list1 = [1, 2, 3] list2 = ['one', 'two', 'three'] print(list_to_dictionary(list1, list2)) 输出: {1: 'one', 2: 'two', 3: 'three'} 10、异常处理 Python提供了try...except...finally的方式来处理代码...