# initialize string text = "Python: How to count words in string Python" substring = "Python" total_occurrences = text.count(substring) print("There are " + str(total_occurrences) + " occurrences.")输出：There ar
words = string.split()#遍历单词列表，更新单词的出现次数 for word in words:if word in word_count:word_count[word] += 1 else:word_count[word] = 1 #找到出现次数最多的单词 max_count = 0 max_word = ""for word, count in word_count.items():if count > max_count:max_count = count ...
new_string="".join(lst).split()returnnew_string src='/tmp/sample.txt'dic={} with open(src,'r') as f:#f.readlines()forlineinf: words_list=line.lower().split()forwordinwords_list:#str in listword = makekey(word)#return listforwordsinword:ifwordsindic.keys(): dic[words]+=1else...
clear() # empty the counter | >>> c | Counter() | | Note: If a count is set to zero or reduced to zero, it will remain | in the counter until the entry is deleted or the counter is cleared: | | >>> c = Counter('aaabbc') | >>> c['b'] -= 2 # reduce the count ...
因为wordcount 使用了string.punctuation来获取所有的标点符号进行了处理,所以会将文本中的所有标点符号替换为空格,之后创建了一个空字典word_count来存储单词及其出现的次数。接着,使用str.maketrans和translate方法将所有标点符号替换为空格。然后,将文本转换为小写,并使用split方法分割成单词列表。最后,遍历单词列表,统计每...
words=re.findall(r'\b\w+\b',string)# 获取单词列表word_list=Counter(words)# 根据单词出现次数进行排序sorted_word_list=sorted(word_list.items(),key=lambdax:x[1],reverse=True)# 输出结果forword,countinsorted_word_list:print(f"{word}:{count}")# 测试代码string="Thisisa test string.It ...
Return centered in a string of length width. Padding is done using the specified fillchar (default is a space). Changed in version 2.4: Support for the fillchar argument. str.count(sub[, start[, end]]) 返回sub子串的数量 Return the number of non-overlapping occurrences of substring sub in...
用Python 实现函数count_words(),该函数输入字符串s和数字n,返回s中n个出现频率最高的单词。返回值是一个元组列表,包含出现次数最高的n个单词及其次数,即[(<单词1>, <次数1>), (<单词2>, <次数2>), ... ],按出现次数降序排列。 您可以假设所有输入都是小写形式,并且不含标点符号或其他字符(只包含字...
count() 方法:S.count(sub[, start[, end]]) -> int Return the number of non-overlapping occurrences of substring sub in string S[start:end]. Optional arguments start and end are interpreted as in slice notation. 查找子字符串 sub 在字符串中出现的次数,可选参数,开始 和 结束 可理解为切片...
for letter1 in range(65,91): #大写字母统计 WD.append(chr(letter1))for letter2 in range(97,123): #小写字母统计 wd.append(chr(letter2))for i in range(26):per = (text.count(wd[i])+text.count(WD[i]))/len(text)per = '{:.2%}'.format(per)sum0 = text.count(wd[i])+...