个人觉得,第二种方法是最容易想到的,因为List中的reverse方法比较常用,做LeetCode题目7. Reverse Integer也用了这种方法,程序耗时65ms #字符串的反转#用到for循环的步长参数,从大到小循环,到0为止defreverse1 (s): rt=''foriinrange(len(s)-1, -1, -1): rt+=s[i]returnrt#用到list的反转函数reverse...
leetcode Reverse Integer python classSolution(object):defreverse(self, x):""":type x: int :rtype: int"""answer=0 sign= 1ifx > 0else-1x=abs(x)whilex >0: answer= answer * 10 + x % 10x/=10ifanswer > 2147483647: answer=0returnsign*answer...
LeetCode 7M Reverse Integer 翻转整数(3种简单解法 with Python) 5 收藏 这个题其实是 LeetCode 9 的基础题。可见,LeetCode 的题目编排就是乱来。 不过呢,相对 LeetCode 9,此题存在一些小的细节必须考虑周全。 题目要求看上去很简单,就是把一个整数从右到左翻过来。比如5,翻过来还是5;123,翻过来就是 321...
def reverse_integer(num): """ :param num: int :return: reverse num """ if not isinstance(num, int): return False num2Str = str(num) n = len(num2Str) if n == 1 or (n == 2 and num2Str[0] == '-'): return num def reverse_handle(start, end, numstr): stack_ = list() ...
[Leetcode][python]Reverse Integer/反转整数 题目大意 反转整数123变为321,-123变为-321 注意:在32位整数范围内,并且001要成为1 假设我们的环境只能存储 32 位有符号整数,其数值范围是 [−2^31, 2^31 − 1]。根据这个假设,如果反转后的整数溢出,则返回 0。
Given a 32-bit signed integer, reverse digits of an integer. note:Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the revers...
[Leetcode][python]Reverse Integer/反转整数 题目大意 反转整数123变为321,-123变为-321 注意:在32位整数范围内,并且001要成为1 假设我们的环境只能存储 32 位有符号整数,其数值范围是 [−2^31, 2^31 − 1]。根据这个假设,如果反转后的整数溢出,则返回 0。
一、题目 Reverse Integer 二、解题 之前做过字符串翻转,首先想到的就是整数符号提取出来(使用sign表示),把整数转化为字符串,然后使用字符串的翻转。 三、尝试与结果 classSolution(object):defreverse(self,x):sign=-1ifx<0else1result=int(str(abs(x))[::-1])ifresult>2**31-1:return0else:returnresult...
Reverse digits of an integer. Example1:x = 123, return 321 Example2:x = -123, return -321 Have you thought about this?Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!If the integer's last digit is 0, what should the...
print("Reversed number: ", reverse_number(number)) In this code, the functionreverse_numberuses Python’s built-in functionsstrandintto convert the input number into a string and then back into an integer. The slicing operation[::-1]is used to reverse the string. ...