解法1:字符串反转 解法2:数学运算(求余)转换 解法3:递归解法 这个题其实是 LeetCode 9 的基础题。可见,LeetCode 的题目编排就是乱来。 不过呢,相对 LeetCode 9,此题存在一些小的细节必须考虑周全。 题目要求看上去很简单,就是把一个整数从右到左翻过来。比如5,翻过来还是5;123,翻过来就是 321;-124,反过...
li.reverse() rt="".join(li)returnrt#用到切片的步长参数,负数代表从右往左遍历defreverse3 (s):returns[::-1]#用到python内建函数reversed(str)defreverse4 (s):return"".join(reversed(s))#用到python内建函数reduce()"""def reduce(function, sequence, initial=None): reduce(function, sequence[,...
7. Reverse Integer 题目链接:Reverse Integer 思路: 因为Python中的数字是没有overflow的,即limit取决于电脑的内存。不过题目有额外要求,假设我们只能处理 32-bit signed 的数字区间。 所以需要另外加一个判断。另外,Python内置的int()函数可以把 "001" 转换成数字 1。 数字要注意区分正负。负数反转还是负数。对于Py...
Reverse Integer Description Given a 32-bit signed integer, reverse digits of an integer. Example 1: Example 2: Example 3: Note: Assume we are dealing with an environment which could only store integers within the 32-...【LeetCode】7. Reverse Integer Introduction Given a 32-bit signed ...
Reverse Integer Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note: Assume we are ...Reverse Integer [size=large][b]题目描述:Reverse digits of an integer. Example...
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[Leetcode][python]Reverse Integer/反转整数 题目大意 反转整数123变为321,-123变为-321 注意:在32位整数范围内,并且001要成为1 假设我们的环境只能存储 32 位有符号整数,其数值范围是 [−2^31, 2^31 − 1]。根据这个假设,如果反转后的整数溢出,则返回 0。
7. Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Note: The input is assumed to be a 32-bit signed intege...Reverse Integer Reverse Integer Given a 32-bit signed integer, reverse digits of an ...
[LeetCode-Easy][Python] 007-Reverse Integer 题目来源 https://leetcode.com/problems/reverse-integer/description/ Descirption:Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321...
Reverse Number using Java program //Java program to Reverse a Number.importjava.util.*;publicclassReverseNumber{publicstaticvoidmain(String[]args){intnumber;Scanner sc=newScanner(System.in);//Read NumberSystem.out.print("Enter an integer number: ");number=sc.nextInt();//calculate reverse numbe...