dfs(board) = True,该行结束 return True def solveSudoku(self, board): """ :type board: List[List[str]] :rtype: void Do not return anything, modify board in-place instead. """ for i in range(9): for j in range(9): c = board[i][j] if c == '.': continue self.seen....
return True def solveSudoku(self, board): """ :type board: List[List[str]] :rtype: void Do not return anything, modify board in-place instead. """ for i in range(9): for j in range(9): c = board[i][j] if c == '.': continue self.seen.add((i, int(c))) self.seen....
leetcode Sudoku Solver python #the define of Sudoku is on this link : http://sudoku.com.au/TheRules.aspx Write a program to solve a Sudoku puzzle by filling the empty cells. Empty cells are indicated by the character'.'. You may assume that there will be only one unique solution. A ...
https://leetcode.com/problems/sudoku-solver/ 题意分析: 这次的题目就是上一题的进化版。填好一个数独。 题目思路: 这题直接用dfs暴力解决。把“*”用(1-9)直接填就行。时间复杂度比较高。要注意的是,题目要求没有返回值,所以要另外写一个函数用来判断填数之后是否满足可以填好。 代码(python): View C...
Poly-Mentor/Sudoku-solver-pythonmain BranchesTags Code Folders and files Latest commit Cannot retrieve latest commit at this time. History3 Commits .gitattributes .gitignore LICENSE easy-example-solution.gif easy-example.gif sudoku.py
Sudoku is a form of puzzle that is three rows and three columns of squares. Each square then holds another three by three set of boxes. This gives a board of 81 boxes that need to be filled with the numbers one through nine. Each row must contain the set from one to nine, each ...
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Sudoku solver implementation in Python. Contribute to zvonimir-rezo/sudoku-solver development by creating an account on GitHub.
https://leetcode.cn/problems/sudoku-solver/ 编写一个程序,通过填充空格来解决数独问题。 数独的解法需 遵循如下规则: 数字1-9 在每一行只能出现一次。 数字1-9 在每一列只能出现一次。 数字1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图) 数独部分空格内已填入了数字,空白格用 ‘....
classsovSudoku:#求解数独 def__init__(self,board=[]):self._b=board.copy()#直接写=board会直接修改传进来的列表 deftrysxy(self,x,y):#主循环,尝试x,y处的解答ifself._b[x][y]==0:#不等于0的情况在调用外处理 pv=self.getPrem(x,y)#forvinrange(1,10):#从1到9尝试forvinpv:self._t+...