这个程序首先创建一个空列表odd_numbers来存储奇数。然后，它使用for循环遍历从 1 到 20 的整数，使用%运算符来检查每个数字是否为奇数（奇数对2取余不等于0）。如果数字是奇数，就将它添加到odd_numbers列表中。最后，程序输出奇数的个数和奇数列表。count = 0 for num in range(1, 21): # 遍历1到20之间的
def print_odd_numbers(n): for i in range(1, n+1): if i % 2 != 0: print(i) n = int(input("请输入一个正整数:")) print_odd_numbers(n) '''draw_flowchart(code,'flowchart.gv') 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 2...
The problem with the following code should be fairly obvious: >>> odd = lambda x : bool(x % 2) >>> numbers = [n for n in range(10)] >>> for i in range(len(numbers)): ... if odd(numbers[i]): ... del numbers[i] # BAD: Deleting item from a list while iterating over...
Python Program to Find Odd and Even Numbers from the List of Integers # Give number of elements present in listn=int(input())# listl=list(map(int,input().strip().split(" ")))# the number will be odd if on diving the number by 2# its remainder is one otherwise number will be ...
for i in range(4): net.append(int(addr[i]) & mask[i]) Don't forget, our original address list was still a string. When we read that in from the command line, it treated the numbers like text. So we used the int function to change that so that we can do the math. The appen...
This sets up the generating loop to run for ten iterations. This means it will print all odd numbers between zero and nine. In order to run a longer generator, enter a higher value for the while loop condition. Step 2 Write the generator code, following the while loop (Remember that in...
>>>defeven(f):...defodd(x):...ifx<0:...returnf(-x)...returnf(x)...returnodd>>>steven=lambda x:x>>>stewart=even(steven)>>>stewart ___>>>stewart(61)___>>>stewart(-4)___>>>defcake():...print('beets')...defpie():...print('sweets')...return'cake'...returnpie>...
is_odd=lambda x:x%2!=0# 使用 filter 函数 filtered_numbers=filter(is_odd,numbers)# 将迭代器转换为列表查看结果print(list(filtered_numbers))# 输出:[1,3,5] 注意:从 Python 3 开始,filter() 直接返回一个迭代器而不是列表,因此如果需要实际的列表或其他容器,通常需要将结果转换为所需的类型。
In this code, theis_evenfunction takes a number as input and uses the modulo operator to check if it is divisible by 2. If the remainder is 0, the function returnsTrueindicating the number is even. Otherwise, it returnsFalsefor odd numbers. ...
Pictorial Presentation of Odd Numbers: Sample Solution: Python Code: # Prompt the user to enter a number and convert the input to an integernum=int(input("Enter a number: "))# Calculate the remainder when the number is divided by 2mod=num%2# Check if the remainder is greater than 0,...