这个程序首先创建一个空列表odd_numbers来存储奇数。然后，它使用for循环遍历从 1 到 20 的整数，使用%...
def print_odd_numbers(n): for i in range(1, n+1): if i % 2 != 0: print(i) n = int(input("请输入一个正整数:")) print_odd_numbers(n) '''draw_flowchart(code,'flowchart.gv') 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 2...
is_odd=lambda x:x%2!=0# 使用 filter 函数 filtered_numbers=filter(is_odd,numbers)# 将迭代器转换为列表查看结果print(list(filtered_numbers))# 输出:[1,3,5] 注意:从 Python 3 开始,filter() 直接返回一个迭代器而不是列表,因此如果需要实际的列表或其他容器,通常需要将结果转换为所需的类型。 👊...
numbers = [1,2,3] my_dict = dict([(number,number*2) for number in numbers]) print(my_dict) # {1: 2, 2: 4, 3: 6} pythonic numbers = [1, 2, 3] my_dict = {number: number * 2 for number in numbers} print(my_dict) # {1: 2, 2: 4, 3: 6} # 还可以指定过滤条件 ...
In this code, theis_evenfunction takes a number as input and uses the modulo operator to check if it is divisible by 2. If the remainder is 0, the function returnsTrueindicating the number is even. Otherwise, it returnsFalsefor odd numbers. ...
‘That’s Odd’ Python help #receive user input and store in list ‘nums’ nums = list(map(int, input().split())) #store even numbers from nums evens = [x for x in nums if x % 2 == 0] #add together all the even numbers print(sum(evens)) Could anyone PLEASE tell me why ...
Pictorial Presentation of Odd Numbers: Sample Solution: Python Code: # Prompt the user to enter a number and convert the input to an integernum=int(input("Enter a number: "))# Calculate the remainder when the number is divided by 2mod=num%2# Check if the remainder is greater than 0,...
[ expression for item in iterable if condition ] Let’s make a new comprehension that builds a list of only the odd numbers between 1 and 5 (remember that number % 2 is True for odd numbers and False for even numbers): >>> a_list = [number for number in range(1,6) if number ...
>>>defeven(f):...defodd(x):...ifx<0:...returnf(-x)...returnf(x)...returnodd>>>steven=lambda x:x>>>stewart=even(steven)>>>stewart ___>>>stewart(61)___>>>stewart(-4)___>>>defcake():...print('beets')...defpie():...print('sweets')...return'cake'...returnpie>...
for i in numbers: if i not in count_freq: count_freq[i] = 1 else: count_freq[i] += 1 for key,value in count_freq.items(): if value > (lens//2): return key return 0 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11.