If the remainder is not zero, the number is odd. Source Code # Python program to check if the input number is odd or even. # A number is even if division by 2 gives a remainder of 0. # If the remainder is 1, it is an odd number. num = int(input("Enter a number: ")) if...
Enter a number: 5 This is an odd number. Explanation: The said code prompts the user to input a number, then converts the input to an integer and assigns it to the variable 'num'. Then it calculates the remainder of 'num' and 2 and assigns it to the variable 'mod'. Next, it ch...
# 直接使用数字字面量表示奇数odd_number = 3print(f"{odd_number} is odd.") # 输出："3 is odd."计算表达：# 使用模运算符判断一个数字是否为奇数num = 7if num % 2 != 0:(tab)print(f"{num} is odd.") # 输出："7 is odd."else:(tab)print(f"{num} is even.") # 输出："7...
在条件语句中，百分号可以用于判断一个数是否为偶数。num = 10 if num % 2 == 0: print("Number is even.") # 输出："Number is even." else: print("Number is odd.") # 输出："Number is odd."这些示例展示了Python中百分号运算符的多种用途。通过这些实例，我们可以更好地理解百分号在...
print(f"\nThe number {number} is odd.") 1. 2. 3. 4. 5. 6. 7. 7.2 while循环简介 for循环用于针对集合中的每个元素都执行一个代码块,而while循环则不断运行,直到指定的条件不再满足为止。 7.2.1 使用while循环 可使用while循环来数数。例如,下面的while循环从1数到5: ...
importtkinterastk# 定义奇偶数判断函数defcheck_odd_even():try:number=int(entry.get())# 获取用户...
We will learn how to check if any given number is even or odd using different techniques, using the subtraction method and using the modulo operator method.
odd_number = (i for i in range(10) if i % 2 != 0)for number in odd_number:print(number) # 输出：1, 3, 5, 7, 9 装饰器与函数奇偶性判断 在Python中，装饰器是一种对函数进行增强或修改的功能。我们可以利用装饰器来创建一个判断函数参数奇偶性的函数。例如：def is_odd(func):(tab)def...
Enter a number: 0 Zero A number is positive if it is greater than zero. We check this in the expression of if. If it is False, the number will either be zero or negative. This is also tested in subsequent expression.Also Read: Python Program to Check if a Number is Odd or Even ...
代码示例如下：num = input("Enter a number, and I'll tell you if it's even or odd:")num = int(num)if num % 2 == 0: print("The number " + str(num) + " is even.")else: print("The number " + str(num) + " is odd.")第二种方法：函数divmod() 取余数 1 ...