6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
Python Code Review: is_leap_year() Python Code Review: days_in_month() Python Code Review: is_valid_date() section Start Travel Set year = 2022 Set month = 2 Set day = 29 Call is_valid_date(year, month, day) section End Travel Check if the date is valid 类图 DateProcessor+is_le...
1、定义一个is_leap(year)函数,该函数可以判度year是否为闰年。若是闰年,则返回True;否则返回False。 import sys def is_leap(year): year = int(year) if year % 4 != 0: return False elif year % 100 != 0: return True elif year % 400 != 0: return False else: return True while(True)...
2. or运算策略：当or运算符连接的两个表达式的值至少有一个为True时，最终的结果会返回第一个表达式的值。如果两个表达式的值都为False，那么or运算会返回False。逻辑运算的应用场景 1. and运算的应用：# 检查一个年份是不是闰年def is_leap_year(year):(tab)return year % 4 == 0 and (year % 100 !=...
Step 1: Make sure the year can be divisible by 4 Step 2: Check if the year is divisible by 100 Step 3: Check if the year is divisible by 400 The output of Leap Year Program In Python: 2024 is a leap year. Also Read: How to check for Armstrong Number in Python? Different Methods...
if __name__ == '__main__': main() 计算指定的年月日是这一年当中的第几天, 提示如下错误: 1 TypeError: is_leap_year() takes 0 positional arguments but 1 was given 问题分析: 报错的意思是:is_leap_year()这个函数不需要参数,但是函数却被传递了一个参数。 掉头检查代码,会发现: 1 def is...
dt=datetime.date(year,month,day) flag=True while True: dt+=datetime.timedelta(days=1) s="{}{:0>2d}{:0>2d}".format(dt.year,dt.month,dt.day) if s[:]==s[::-1]: if flag: print(s) flag=False if s[0]==s[2]==s[5]==s[7] and s[1]==s[3]==s[4]==s[6]: ...
(year % 400 == 0) def main(): try: year = int(input("Input a valid year: ")) if check_leap_year(year): print(f"{year} is a leap year.") else: print(f"{year} is not a leap year.") except ValueError: print("Invalid input. Please input a valid year.") if __name__ ...
Although we have multiple conditions for a leap year we can combine all those conditions in only one if statement using AND and OR operators. Let us create a function with only one if statement. python defis_leap(year):# variable to check the leap yearleap =False# One if statement that...
Python Leap Year #The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print("Not a leap year...