Python program to check leap year by using the calendar module # importing the moduleimportcalendar# input the yearyear=int(input('Enter the value of year: '))leap_year=calendar.isleap(year)# checking leap yearifleap_year:# to check conditionprint('The given year is a leap year.')else:...
Here are a few steps to check: is 2024 a Leap Year? Step 1: Make sure the year can be divisible by 4 Step 2: Check if the year is divisible by 100 Step 3: Check if the year is divisible by 400 The output of Leap Year Program In Python: 2024 is a leap year. Also Read: How...
6.程序实现的功能:输人某年某月某日,判断这一天是这一年的第几天,Python代码如下: d e f leap(year):$$ l e a p = 0 $$$ i f ( y e a r \% 4 0 0 = = 0 ) o r ( ( y e a r \% 4 = = 0 ) a n d ( y e a r \% 1 0 0 ! = 0 ) ) : $$$ l e a ...
• The century year is a leap year only if it is perfectly divisible by 400. For example, 2000 is a leap year. Python Program to Check Leap Year #In this leap year python program, the user to asked enter a year. The program checks whether the entered year is a leap year or not....
defis_leap(year):# variable to check the leap yearleap =False# One if statement that contains multiple conditionsif((year %400==0)and(year %100==0)) | ((year %4==0)and(year %100!=0)):# change leap to Trueleap =Truereturnleap ...
5. Leap Year ValidatorWrite a Python program that checks whether a given year is a leap year or not using boolean logic.Sample Solution:Code:def check_leap_year(year): return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) def main(): try: year = int(input("...
Python program to check the given date is valid or not # Importing datetime moduleimportdatetime# Input the date as integers and mapping# it to store the values to d, m, and y variablesd,m,y=map(int,input("Enter date: ").split())try: s=datetime.date(y,m,d)print("Date is valid...
Python Leap Year #The test case is passing 4/6. I don't know what is wrong with my code, please help year = int(input()) if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: print("Leap year") else: print("Not a leap year") else: print("Not a leap year...
1 TypeError: is_leap_year() takes 0 positional arguments but 1 was given 问题分析: 报错的意思是:is_leap_year()这个函数不需要参数,但是函数却被传递了一个参数。 掉头检查代码,会发现: 1 def is_leap_year(): 这里出了问题,我们对其进行修改: 1 def is_leap_year(year): 再次运行代码,成功...
Now, if the year does not follow any of the conditions mentioned above, we conclude that the year is not a leap year. Example Code: yearValue=int(input("Enter a year: "))# here, yearValue means the year we want to check.ifyearValue%4==0andyearValue%100!=0:# condition 2print(ye...