date_feats['dow_text_l']='Monday'date_feats['dow_text_s']='Mon'ifdow=='2':date_feats['dow_text_l']='Tuesday'date_feats['dow_text_s']='Tue'ifdow=='3':date_feats['dow_text_l']='Wednesday'date_feats['dow_text_s']='Wed'ifdow=='4':date_feats['dow_text_l']='Thursday...
today=datetime.date.today() oneday=datetime.timedelta(days=1) yesterday=today-oneday return yesterday #今天 def getToday(): return datetime.date.today() #获取给定参数的前几天的日期,返回一个list def getDaysByNum(num): today=datetime.date.today() oneday=datetime.timedelta(days=1) li=[] for...
#encode=utf-8 from datetime import datetime,timedelta weekdays = ['Monday','Tuesday','Wednesday','Thursday','Friday','Saturday','Sunday'] def get_previous_byday(dayname,start_date=None): if start_date is None: start_date = datetime.today() #获取当前时间 day_num = start_date.weekday(...
复制 importos得到当前工作目录,即当前Python脚本工作的目录路径:os.getcwd()返回指定目录下的所有文件和目录名:os.listdir()函数用来删除一个文件:os.remove()删除多个目录:os.removedirs(r“c:\python”)检验给出的路径是否是一个文件:os.path.isfile()检验给出的路径是否是一个目录:os.path.isdir()判断是否...
checkcode = '' for i in range(4): current = random.randrange(0,4) if current != i: temp = chr(random.randint(65,90)) 1. 2. 3. 4. 5. 6. else: temp = random.randint(0,9) checkcode += str(temp) print checkcode
from datetime import datetime def is_weekday(): today = datetime.today() # Python's datetime library treats Monday as 0 and Sunday as 6 return (0 <= today.weekday() < 5) # Test if today is a weekday assert is_weekday() Since you’re testing if today is a weekday, the resul...
if Money[:3] in ['RMB']: a=(eval(Money[3:])/7.00) print("USD{:.2f}".format(a)) elif Money[:3] in ['USD']: b=(eval(Money[3:])*7.00) print("RMB{:.2f}".format(b)) else: print("输入格式错误") 1. 2. 3.
) while True: # 检查是否是交易日Check if Monday-Friday # if datetime.datetime....
Is there a difference in how a large organization practices code review compared to a smaller one? What do you do if you're a solo developer? This week on the show, Brendan Maginnis and Nick Thapen from Sourcery return to talk about code review and automated code assistance. Play Episode...
if (i//high_step)%2 ==1: if j == long-long_step: draw_circle(long_step//2) continue draw_circle(long_step // 2) pen_skip(long_step) else: if j == long-long_step: draw_circle(-long_step // 2) continue draw_circle(-long_step // 2) pen_skip(long_step) if (i//50)...