下面是一个简单的Python代码示例,用于判断输入的日期是否是周末: importdatetimedefis_weekend(date_str):date_obj=datetime.datetime.strptime(date_str,'%Y-%m-%d')day_of_week=date_obj.weekday()ifday_of_weekin[5,6]:returnTrueelse:returnFalsedate='2022-01-01'ifis_weekend(date):print(f'{date}is...
{'date': '2021-07-20', 'days_from_today': 6, 'dom': '20', 'dow_num': '2', 'dow_text_l': 'Tuesday', 'dow_text_s': 'Tue', 'doy': '201', 'is_day_after_holiday': False, 'is_day_before_holiday': False, 'is_holiday': False, 'is_weekday': True, 'is_weekend': ...
# importing Pandas module import pandas as pd # Creating a Function def check_weekday(date): # computing the parameter date # with len function res=len(pd.bdate_range(date,date)) if res == 0 : print("This is weekend") else: print("This is your working day") # user input date ...
AI代码解释 >>>len(unreadThreads)2>>>str(unreadThreads[0])"<GmailThread len=2 snippet= Do you want to watch RoboCop this weekend?'>">>>len(unreadThreads[0].messages)2>>>str(unreadThreads[0].messages[0])"<GmailMessage from='Al Sweigart <al@inventwithpython.com>'to='Jon Doe<example...
前一个星期天是:next_day(date_sub(current_date, 7), 'SUN') 上周六是:next_day(date_sub(current_date, 7), 'SAT') 我想你需要在星期天之前(减去-14) Select * from tableA where date between next_day(date_sub(current_date, 14), 'SUN') and next_day(date_sub(current_date, 7), 'SAT...
('Learning', 'Python', 101, 'is', 'important.')``'Learning Python 101 is important.'` | | ③ | `>>> '{} | {} | {}'.format ('bread', 'quantity', 'date')``bread | quantity | date``>>> '{} | {} | {}'.format ('bagel', '100'...
Similarly, the fake return value in .test_is_weekend() is a Saturday, and is_weekday() must return False. That’s it! Now, your tests will always work, regardless of the date, because you’ve patched the default behavior of .today() to make it return a fixed date....
(p < d) { p.setDate(p.getDate() + 1) if (p.getDay() == 1) { week++; } } return week;}function formatDate(date) { return (date.toISOString()).split("T")[0];}function getWeekEnd(date, maxDate) { var p = new Date(date.getTime()); var month = p.getMonth(); while ...
notdesired.To learn more about the frequency strings, please see `this link<https://pandas.pydata.org/pandas-docs/stable/user_guide/timeseries.html#offset-aliases>`__.Examples---Note how the two weekend days are skipped in the result.>>> pd.bdate_range(start='1/1/2018', end='1/0...
If this command produces no output, the assertion was successful. Unfortunately, if you run the command on a weekend, you’ll get an AssertionError: Shell $ python holidays.py Traceback (most recent call last): File "/path/to/holidays.py", line 9, in <module> assert is_weekday() ...